得到平日和周末的计数，用PHP给出两个日期

Question

我试图计算两个日期之间的工作日和周末的计数，但是对于周末我得到0值。

以下是代码：

<?php

function daysCount($startDate, $endDate)
{
    $weekdayCount = $weekendCount  =0;
    $startTimestamp = strtotime($startDate);
    $endTimestamp = strtotime($endDate);

    for ($i = $startTimestamp; $i <= $endTimestamp; $i = $i + (60 * 60 * 24))
    {
        if (date("N", $i) <= 5)
        {

            $weekdayCount = $weekdayCount + 1;

        }
        if (date("N", $i) == 6 && $i%7 == 0 )
        {
            $weekendCount = $weekendCount + 1;
        }
    }
    return array('weekdayCount' => $weekdayCount, 'weekendCount' => $weekendCount);
}

$startDate = "2017-07-03";
$endDate = "2017-07-10";
$days = daysCount($startDate, $endDate);
print_r($days);

?>

这是演示链接demo updated

有人可以帮助我获得周末计划吗？

Answer 1

也许这样，基于演示链接：

function number_of_working_days($startDate, $endDate)
{
    $workingDays = 0;
    $startTimestamp = strtotime($startDate);
    $endTimestamp = strtotime($endDate);
    for ($i = $startTimestamp; $i <= $endTimestamp; $i = $i + (60 * 60 * 24)) {
        if (date("N", $i) <= 5) $workingDays = $workingDays + 1;
    }
    return $workingDays;
}

function number_of_weekend_days($startDate, $endDate)
{
    $weekendDays = 0;
    $startTimestamp = strtotime($startDate);
    $endTimestamp = strtotime($endDate);
    for ($i = $startTimestamp; $i <= $endTimestamp; $i = $i + (60 * 60 * 24)) {
        if (date("N", $i) > 5) $weekendDays = $weekendDays + 1;
    }
    return $weekendDays;
}

$startDate = "2016-11-01";
$endDate = "2016-11-30";
$workingDays = number_of_working_days($startDate, $endDate);
$weekendDays = number_of_weekend_days($startDate, $endDate);
echo "Total number of working days between $startDate and $endDate is: " . $workingDays . " day(s).";
echo "Total number of weekend days between $startDate and $endDate is: " . $weekendDays . " day(s).";