Count per category

Question

have a table as below -

COL1  |  COL2  |  COL3
1        1        1
1        1        2
1        2        0
1        2        1
2        3        1
2        3        2
2        4        0
2        4        1
3        1        0
3        2        0     
.
.
.

I want to select COL1 where all COL2 have sum(COL3) is > 0. If I am sure there are 20 distinct values in COL2, Then how can i pull all COL1 values that have all 20 COL2 filled with COL3 > 0. So the end result should be

COL1  |  COL2  |  COL3
1        1        3
1        2        1
2        3        3
2        4        1

I have tried a lot of ways to do this but no success.

Answer 1

Just use group by and having.

select col1,col2,sum(col3)
from tbl
group by col1,col2
having sum(col3)>0

Answer 2

I use a CTE and a Group by with a where condition

;WITH CTE as (
select COL1,COL2,SUM(COL3) as COL3  FROM table1  
Group By
COL1,COL2
)
select * from CTE 
where COL3>0

Answer 3

select t1.*
from yourTable t1
inner join
(
    select t.col1
    from
    (
        select col1, col2, sum(col3) as col_sum
        from yourTable
        group by col1, col2
    ) t
    group by t.col1
    having sum(case when t.col_sum = 0 then 1 else 0 end) = 0
) t2
    on t1.col1 = t2.col1

Answer 4

只需将col2分组并检查它是否大于0

select col1,col2,sum(col3)
from tbl
group by col2
having sum(col3)>0

http://sqlfiddle.com/#!9/537f8c/1

Answer 5

看看下面是否为您提供了您所追求的结果。它是从派生（？）表中选择col1，col2和col3之和，该表排除了0的col3：

select col1, col2, sum(col3)
from
(
    select col1, col2, col3 from tbl where col3 <> 0
) as ds
group by col3