处理json文件的一部分

时间:2017-07-11 10:29:41

标签: java genson

我有一个json文件,看起来像这样

{
  "races": [
    {
      "name"  : "ORC"
    },
    {
      "name"  : "HUMAN"
    },
    {
      "name"  : "ELF"
    }
  ],
  "npc": [
    {
      "race"  : "HUMAN",
      "age"   : "25",
      "name"  : "Jerome"
    },
    {
      "race"  : "ORC",
      "age"   : "26",
      "name"  : "Rz'Ul"
    }
  ]
}

我想根据需要分别从racesnpc检索数据。我正在使用genson来解析JSON。我像这样解析它

@SuppressWarnings("unchecked")
public static <T> List<T> readJsonList(String listName) {
    Genson genson = JsonContext.PARSER.getParser();
    List<T> result = null;
    try (InputStream is = JsonDataProcessor.class.getResourceAsStream(FILE)) {
        ObjectReader reader = genson.createReader(is);
        reader.beginObject();
        while (reader.hasNext()) {
            reader.next();

            if ("races".equals(listName) && "races".equals(reader.name())) {
                result = (List<T>) processRaceData(reader);
                break;
            }

            if ("npc".equals(listName) && "npc".equals(reader.name())) {
                result = (List<T>) processNpcData(reader);
                break;
            }

        }
        reader.endObject();
    } catch (IOException e) {
        e.printStackTrace();
    }

    return result;
}

例如,解析races的方法就像这样

private static List<Race> processRaceData(ObjectReader reader) {
    List<Race> raceList = new ArrayList<>();
    reader.beginArray();
    while (reader.hasNext()) {
        reader.next();

        Race race = new Race();
        reader.beginObject();
        while (reader.hasNext()) {
            reader.next();

            if ("name".equals(reader.name())) { race.setName(reader.valueAsString()); }
            else { reader.skipValue(); }
        }
        reader.endObject();
        raceList.add(race);
    }
    reader.endArray();
    return raceList;
}

调试它populates变量result就好了,但在endObject行我得到了异常

Exception in thread "main" com.owlike.genson.stream.JsonStreamException: Illegal character at row 11 and column 4 expected } but read ',' !
        at com.owlike.genson.stream.JsonReader.newWrongTokenException(JsonReader.java:942)
        at com.owlike.genson.stream.JsonReader.end(JsonReader.java:428)
        at com.owlike.genson.stream.JsonReader.endObject(JsonReader.java:177)
        at com.lapots.breed.platform.json.JsonDataProcessor.readJsonList(JsonDataProcessor.java:41)
        at com.lapots.breed.platform.Example.prepareDb(Example.java:18)
        at com.lapots.breed.platform.Example.main(Example.java:23)

有什么问题?

2 个答案:

答案 0 :(得分:2)

我使用了您的代码,发现 genson 希望关闭对象并在您致电}时检查endObject符号。您只需要使用reader.skipValue()跳过对象。因此,while方法中的readJsonList块中存在错误。这段代码应该对你有用:

 @SuppressWarnings("unchecked")
 public static <T> List<T> readJsonList(String listName) {
 . . .
 while (reader.hasNext()) {
     reader.next();
     if ("races".equals(listName) && "races".equals(reader.name())) {
         result = result = (List<T>) processRaceData(reader);
         break;
     }
     if ("npc".equals(listName) && "npc".equals(reader.name())) {
         result = result = (List<T>) processNpcData(reader);
         break;
     }
     reader = reader.skipValue();
 }
 reader.endObject();
 . . .

答案 1 :(得分:0)

为什么不使用Genson的数据绑定功能并让它为您执行skipValue和mapping? 你可以定义两个数据结构,一个用于比赛,另一个用于npc,然后像这样反序列化它们:

class Races {
  public List<Race> races;
}

class Npcs {
  public List<Npc> npc;
}

// This will skip npc and all the fields in it
Races races = genson.deserialize(inputStream, Races.class);

与使用低级流API编写反序列化相比,这仍然非常有效且不易出错。

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