Question

我有一个日历和一个房间实体。

我的日历实体如下所示：

public class CalendarEntity {

    @EmbeddedId
    private CalendarId calendarId = new CalendarId();

    @Basic
    @Column(name = "available", nullable = false)
    private Boolean available;

    @Basic
    @Column(name = "price")
    private double price;

    @ManyToOne
    @JoinColumn(name = "room_id", referencedColumnName = "id", insertable = 
    false, updatable = false)
    private RoomEntity roomEntity;

}
    @Embeddable
    public class CalendarId implements Serializable {

        @Column(name= "date", nullable = false)
        private Date date;

        @Column(name = "room_id", nullable = false)
        private Integer room_id;
}

我的房间实体看起来像这样：

public class RoomEntity {

    @Id
    @GeneratedValue(strategy = GenerationType.SEQUENCE)
    @Column(name = "id", nullable = false, unique = true)
    private Integer id;
}

我们假设我在日历实体中有一些条目2017-10-5， 2017-10-6,2017-10-7,2017-10-8 with room_id = 10.

我想构建一个查询，这样如果用户要求一个房间有一定的签到和结账日期，那么他将获得正确的房间列表。

我该怎么做？

例如，用户要求checkin = 2017-10-6和checkout = 2017-10-8的房间，房间应该出现在列表中。

查询应该是什么，以便我得到正确的房间列表？

更新：

我现在的查询只检查房间是否在登记日期和结帐日期可用，但不在之间：

select r from RoomEntity r where r.id in (Select c1.calendarId.room_id from CalendarEntity c1, CalendarEntity c2 where (c1.calendarId.room_id = c2.calendarId.room_id)  and (c1.calendarId.date =:checkin and c1.available=true) and(c2.calendarId.date =:checkout and c2.available=true))

Answer 1

方法是：SELECT count（c.calendarId.room_id），c.calendarId.room_id FROM CalendarEntity c WHERE c.available = true和c.calendarId.date BETWEEN：checkin and：checkout GROUP BY c.calendarId.room_id HAVING count（c.calendarId.room_id）＆gt; =：noOfDays noODays表示从签入和退房日期计算的天数。

Answer 2

SELECT r FROM RoomEntity r 
WHERE r.id 
in (select c1.calendarId.room_id 
    FROM CalendarEntity c1 JOIN CalendarEntity c2 
    WHERE c1.calendarId.room_id = c2.calendarId.room_id  
    AND ((c1.calendarId.date BETWEEN :checkin AND :checkout) 
         AND (c1.available=true and c2.available=true));

JPQL checkif room可在日期

2 个答案: