Question

我有以下代码产生以下输出： -

<?
$tablaes = mysql_query("SELECT * FROM members where id='$order[user_id]'"); 
$user = mysql_fetch_array($tablaes);
$idsd=$user['id'];
$rPaid=mysql_query("SELECT SUM(`price`) AS total FROM order_history WHERE type!='rent_referral' AND date>'" . strtotime($time1) . "' AND date<'" . strtotime($time2) . "'");
$hdPaid = mysql_fetch_array($rPaid);
$sPaid=mysql_query("SELECT SUM(`price`) AS total FROM order_history WHERE user_id='$idsd' AND type!='rent_referral' AND date>'" . strtotime($time1) . "' AND date<'" . strtotime($time2) . "'");
while ($hPaid = mysql_fetch_array($sPaid)) { 
?>

<td><?=$user['username']?></td>
<td><?=$hPaid['total']?></td>
<?  
}
?>

</tr>

看起来像http://dl.dropbox.com/u/14384295/darrenan.jpg

我希望相同的数据只出现一次..

喜欢用户名：拉斯维加斯和他只有一次价格。

Answer 1

尝试更改

$sPaid=mysql_query("SELECT SUM(`price`) AS total FROM order_history WHERE user_id='$idsd' AND type!='rent_referral' AND date>'" . strtotime($time1) . "' AND date<'" . strtotime($time2) . "'");

到

$sPaid=mysql_query("SELECT SUM(`price`) AS total FROM order_history WHERE user_id='$idsd' AND type!='rent_referral' AND date>'" . strtotime($time1) . "' AND date<'" . strtotime($time2) . "' GROUP BY user_id");

Answer 2

改变它

$sPaid=mysql_query("SELECT SUM(`price`) AS total FROM order_history WHERE user_id='$idsd' AND type!='rent_referral' AND date>'" . strtotime($time1) . "' AND date<'" . strtotime($time2) . "'");

到

$sPaid=mysql_query("SELECT SUM(`price`) AS total FROM order_history WHERE user_id='$idsd' AND type!='rent_referral' AND date>'" . strtotime($time1) . "' AND date<'" . strtotime($time2) . "' limit 1");

Answer 3

更改到$tablae = mysql_query("SELECT * FROM order_history where date>'" . strtotime($time1) . "' AND date<'" . strtotime($time2) . "' GROUP BY user_id");

抱歉没有在第一篇文章中添加tablae。无论如何解决了。

Answer 4

您可以在“选择”查询中使用“DISTINCT”以避免重复结果中的数据。

相同数据仅出现一次

4 个答案: