Question

我正在尝试从下面的输出中获取特定值。我试图获得＆＃34; package_path＆＃34;的价值。我试图找到最好的方法来做到这一点。我试过iteritems()，但它似乎没有提供正确的值输出。我还有另一种方式吗？...谢谢..

[{"name": "ZONE", "value": "zone01"}, 
 {"name": "VPCNetworkCIDRs", "value": "192.168.30.0/24"}, 
 {"name": "DEPLOYMENT_ENVIRONMENT", "value": "AWS"}, 
 {"name": "parameters_json", "value": "s3://my_folder/zone01/zone01.json"}, 
 {"name": "REGION", "value": "us-east-1"}, 
 {"name": "SECTOR", "value": ""}, 
 {"name": "package_path", "value": "s3://my_bucket/packages/my_app.1.0.2.0.pkg"}, 
 {"name": "component_type", "value": "WebApplication"}, 
 {"name": "PROFILE", "value": "dev"}]

Answer 1

由于你拥有的是词典列表，你必须遍历他们的name属性才能找到你想要的词典。

my_list = [{"name": "ZONE", "value": "zone01"}, {"name": "VPCNetworkCIDRs", "value": "192.168.30.0/24"},
 {"name": "DEPLOYMENT_ENVIRONMENT", "value": "AWS"},
 {"name": "parameters_json", "value": "s3://my_folder/zone01/zone01.json"}, {"name": "REGION", "value": "us-east-1"},
 {"name": "SECTOR", "value": ""}, {"name": "package_path", "value": "s3://my_bucket/packages/my_app.1.0.2.0.pkg"},
 {"name": "component_type", "value": "WebApplication"}, {"name": "PROFILE", "value": "dev"}]



package_path = None

# For each name/value pair in my_list...
for name_value in my_list:
    # If the name attribute is package_path, we found it
    if name_value['name'] == 'package_path':
        package_path = name_value['value']  # Store our variable
        break # Exit the loop

if package_path is None:
    print('Package path not found :(')
else:
    print(package_path)  # s3://my_bucket/packages/my_app.1.0.2.0.pkg

Answer 2

考虑将数据结构重新格式化为单个字典。例如，使用：

data = dict((item['name'], item['value']) for item in items)

然后：

print(data['package_path'])

将为您提供所需内容，以及其他类似内容。

Answer 3

您可以使用列表理解。

[arg['value'] for arg in my_list if arg['name'] == 'package_path']

迭代通过响应并通过Python获取值

3 个答案: