我正在尝试使用Sendgrid发送密码重置电子邮件。
以下是错误的堆栈跟踪:
Traceback (most recent call last):
File "C:\Program Files\Google\google_appengine\lib\webapp2-
2.5.2\webapp2.py", line 1535, in __call__
rv = self.handle_exception(request, response, e)
File "C:\Program Files\Google\google_appengine\lib\webapp2-
2.5.2\webapp2.py", line 1529, in __call__
rv = self.router.dispatch(request, response)
File "C:\Program Files\Google\google_appengine\lib\webapp2-
2.5.2\webapp2.py", line 1278, in default_dispatcher
return route.handler_adapter(request, response)
File "C:\Program Files\Google\google_appengine\lib\webapp2-
2.5.2\webapp2.py", line 1102, in __call__
return handler.dispatch()
File "C:\Program Files\Google\google_appengine\lib\webapp2-
2.5.2\webapp2.py", line 572, in dispatch
return self.handle_exception(e, self.app.debug)
File "C:\Program Files\Google\google_appengine\lib\webapp2-
2.5.2\webapp2.py", line 570, in dispatch
return method(*args, **kwargs)
File "C:\Users\C\PycharmProjects\alpha\u\user.py", line 121, in post
response = sg.client.mail.send.post(request_body=mail.get())
File "C:\Users\C\PycharmProjects\alpha\python_http_client\client.py",
line 227, in http_request
return Response(self._make_request(opener, request))
File "C:\Users\C\PycharmProjects\alpha\python_http_client\client.py",
line 161, in _make_request
raise exc
UnauthorizedError
我已将sendgrid和python-http-client导入到我的项目中。 (为什么我必须单独导入它?)
以下是我从Sendgrid演示中获取的测试代码:
class PasswordResetHandler(BaseHandler):
"""
handler to reset the users password.
also to verify if the user email is in the database
"""
def post(self):
email = self.request.get("email_for_reset")
sg = sendgrid.SendGridAPIClient(apikey=os.environ.get(SENDGRID_API_KEY))
from_email = Email("email@example.com")
to_email = Email(email)
subject = "Sending with SendGrid is Fun"
content = Content("text/plain", "and easy to do anywhere, even with Python")
mail = Mail(from_email, subject, to_email, content)
response = sg.client.mail.send.post(request_body=mail.get())
self.redirect('/u/password-reset-confirmation')
任何人都可以帮忙解决这里发生的事情吗?
感谢。
答案 0 :(得分:0)
我使用的语法不同,使用SendGridClient
:
sg = sendgrid.SendGridClient(SENDGRID_API_KEY)
message = sendgrid.Mail(
to = to,
subject = subject,
html = html,
text = body,
from_email = sender
)
status, msg = sg.send(message)
答案 1 :(得分:0)
检查您的API密钥是否存在拼写错误,并确保使用os.environ.get()
正确加载。
您收到HTTP错误401.正如您在第161行(及其前面的行)上看到in the client.py code包含_make_request
的那样,您将收到第159行中正在处理的HTTPError :
exc = handle_error(err)
handle_error()
已实现in exceptions.py,并显示UnauthorizedError
来自HTTPError 401.最可能的原因是错误的api密钥。检查你的api密钥是否有拼写错误。通过在我的代码中插入一个错误的api密钥,我能够得到相同的HTTP错误。除此之外,我有这个功能使用您在问题中显示的相同代码。