protobuf-net是否支持名为元组?

时间:2017-07-20 09:40:33

标签: c# protocol-buffers protobuf-net

protobuf-net是否支持named tuples的序列化?

例如

SELECT 
COUNT(main_dish),
COUNT(soup_stew),
COUNT(meat_fish),
COUNT(other),
COUNT(main_dish) + COUNT(soup_stew) + COUNT(meat_fish) + COUNT(other) AS 'total' FROM foodlist;

1 个答案:

答案 0 :(得分:3)

“部分是,部分不是”。

protobuf-net没有命名元组的特定知识the names are not available to library code,但从v2.2.0起,protobuf-net 推断出ValueTuple<...>类型的合同,主要将其视为位置类型 - 因此Bid将为字段1,Ask将为字段2,等等。GetProto<T>等代码将< em> not 产生你期望的结果(因为a:它看不到名字,而b:大型元组的形状变得很奇怪),你将无法控制细粒度的序列化细节(DataFormat等),但是:它应该有效。

以下工作正常:

using ProtoBuf;
using System.Collections.Generic;

static class P
{
    static void Main()
    {
        var obj = new MyType { FuturesCurveData = {
                { 1.0, (1, 2, 3, 4, 5, 6, 7, 8) },
                { 2.0, (2, 3, 4, 5, 6, 7, 8, 9) },
            } };
        var clone = Serializer.DeepClone(obj);
        foreach(var pair in clone.FuturesCurveData)
        {
            System.Console.WriteLine($"{pair.Key}: {pair.Value}");
        }
    }
}
[ProtoContract]
class MyType
{
    [ProtoMember(1)]
    public SortedDictionary<double, (double Bid, double Ask, double Open, double High, double Low, double Close, int Volume, int OpenInt)> FuturesCurveData { get; } =
    new SortedDictionary<double, (double Bid, double Ask, double Open, double High, double Low, double Close, int Volume, int OpenInt)>();
}

输出:

1: (1, 2, 3, 4, 5, 6, 7, 8)
2: (2, 3, 4, 5, 6, 7, 8, 9)

这就是GetProto<MyType>()所产生的 - 并不是那么成功:

syntax = "proto2";
package System;

message KeyValuePair_Double_ValueTuple_Double_Double_Double_Double_Double_Double_Int32_ValueTuple_Int32 {
   optional double Key = 1;
   optional ValueTuple_Double_Double_Double_Double_Double_Double_Int32_ValueTuple_Int32 Value = 2;
}
message MyType {
   repeated KeyValuePair_Double_ValueTuple_Double_Double_Double_Double_Double_Double_Int32_ValueTuple_Int32 FuturesCurveData = 1;
}
message ValueTuple_Double_Double_Double_Double_Double_Double_Int32_ValueTuple_Int32 {
   optional double Item1 = 1;
   optional double Item2 = 2;
   optional double Item3 = 3;
   optional double Item4 = 4;
   optional double Item5 = 5;
   optional double Item6 = 6;
   optional int32 Item7 = 7;
   optional ValueTuple_Int32 Rest = 8;
}
message ValueTuple_Int32 {
   optional int32 Item1 = 1;
}

作为旁注,如果密钥类型为map<,>int,则作为string工作,但它似乎遇到了错误,I have logged

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