在PHP和MYSQL上的同一行上选择SUM和COUNT

Question

我有两个表，客户端和事务，我试图在同一行显示来自同一客户端的所有事务的SUM和COUNT，以及交易的类型，但我不知道如何对它进行分组，因此它只显示一个客户端的总数，而下一行是另一个客户端的总数，而不是重复它。感谢您的时间。

  

表客户

     

id_client - client_name

     

表交易

     

id_transaction - client_id - date - type - amount

&approx_contour[0]

Answer 1

按客户ID分组，并选择交易ID的金额和计数总和：

$query = " SELECT clients.client_name, transacctions.type
SUM(transacctions.amount) AS sum_amount,
COUNT(transacctions.id_transaction) AS transaction_count
FROM  transacctions, clients
WHERE (transacctions.date BETWEEN '$date1' AND '$date2') 
AND transactions.client_id = clients.id_client 
AND transactions.type = '$type' 
GROUP BY clients.id_client; "

或者，建议使用连接。这将给你相同的结果：

$query = " SELECT clients.client_name, transacctions.type
SUM(transacctions.amount) AS sum_amount,
COUNT(transacctions.id_transaction) AS transaction_count
FROM  clients
INNER JOIN transacctions ON transactions.client_id = clients.id_client 
WHERE (transacctions.date BETWEEN '$date1' AND '$date2') 
AND transactions.type = '$type' 
GROUP BY clients.id_client; "

如果您想查看所有客户，包括没有交易的客户，请将INNER JOIN更改为LEFT JOIN：

$query = " SELECT clients.client_name, transacctions.type
SUM(transacctions.amount) AS sum_amount,
COUNT(transacctions.id_transaction) AS transaction_count
FROM  clients
LEFT JOIN transacctions ON transactions.client_id = clients.id_client 
WHERE (transacctions.date BETWEEN '$date1' AND '$date2') 
AND transactions.type = '$type' 
GROUP BY clients.id_client; "

注意：我没有修复＆＃34;交易错误＃34;在你的查询中，因为我不确定它是否是一个错字或你的表实际上有这个名字。