ItemTemplate中ListView项目中的MVVM绑定按钮

时间:2017-07-22 20:15:26

标签: c# xaml mvvm uwp template10

在使用MVVM和Template10的UWP-Windows 10 C#/ XAML应用程序中,我目前正试图通过以下方式将ListView项目中的按钮绑定到ViewModel中的方法:

<Page.Resources>
    <DataTemplate x:DataType="vm:ViewModel" x:Key="TermListViewTemplate">
        <Grid>
            <ListView x:Name="termListView" 
                      ItemsSource="{x:Bind childModels, Mode=OneWay}"
                      ItemClick="EntityListClick">
                <ListView.ItemTemplate>
                    <DataTemplate x:DataType="gl:Term">
                        <Grid HorizontalAlignment="Stretch">
                            <StackPanel>
                                <Button Click="EditButton_Click">
                                    <SymbolIcon Symbol="Edit"></SymbolIcon>
                                </Button>
                                <Button Click="DeleteButton_Click">
                                    <SymbolIcon Symbol="Delete"></SymbolIcon>
                                </Button>
                            </StackPanel>
                        </Grid>
                    </DataTemplate>
                </ListView.ItemTemplate>
            </ListView>
        </Grid>
    </DataTemplate>
</Page.Resources>

EntityListClickEditButton_ClickDeleteButton_Click是代码隐藏文件中的所有方法,然后在ViewModel中调用方法,如下所示:

private void EntityListClick(object sender, ItemClickEventArgs e)
{
    ViewModel.termClick((Term)e.ClickedItem);
}

private void EditButton_Click(object sender, Windows.UI.Xaml.RoutedEventArgs e)
{
    ViewModel.editTerm((Term)(sender as Button).DataContext);
}

private void DeleteButton_Click(object sender, Windows.UI.Xaml.RoutedEventArgs e)
{
    ViewModel.deleteTerm((Term)(sender as Button).DataContext);
}

如何在此方案中正确实现MVVM模式,以便在ViewModel.termClick中直接绑定到ViewModel.editTermViewModel.deleteTermViewModel,同时将正确的参数传递给ViewModel

此外,我在XAML中有一个按钮,其Click事件处理程序附加到后面的代码中的以下方法:

private async void AddTerm_Click(object sender, Windows.UI.Xaml.RoutedEventArgs e)
{
    await ViewModel.addTermAsync();
    ListView termListView = (ListView)((Grid)((Button)sender).Parent).Children[2];
    termListView.ScrollIntoView(termListView.Items[termListView.Items.Count - 1]);
}

再次,是否有一些方法可以直接将点击处理程序直接链接到ViewModel,以便可以滚动ListView? (也许某种方式将ListView的整个实例绑定到类型&#34; ListView&#34;在ViewModel中的属性?)

0 个答案:

没有答案
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