Question

假设我有一个包含2行的分割器。

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如何进入此

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从水平分割切换到垂直分割

无需重新创建整个拆分器？

代码是：

if (!m_wndSplitter.CreateStatic(this, 1, 2, WS_CHILD|WS_VISIBLE))
{
    TRACE0("Failed to create splitter window\n");
    return FALSE;
}
if (!m_wndSplitter.CreateView(0, 1, RUNTIME_CLASS(CWnd), CSize(200, 100), NULL))
{
    TRACE0("Failed to create CView1\n");
    return FALSE;
}
if (!m_wndSplitter.CreateView(0, 2, RUNTIME_CLASS(CWnd), CSize(500, 100), NULL))
{
    TRACE0("Failed to create CView2\n");
    return FALSE;
}

Answer 1

请勿使用CreateStatic，只需在分割器上使用Create即可。然后你有一个所谓的动态分割器，请参阅更多here。

将分割器从horz转换为vert时，您必须从分割器中删除视图，然后再将它们连接起来。您必须在文档类中执行此操作。如果需要，我可以发布一个方法来执行此操作。

好的，这是一种在窗格中切换视图的方法：

CView* CGMBefundDoc::SwitchToView(CView* pNewView,int row,int col)
{
CMainFrame* pMainWnd = (CMainFrame*)AfxGetMainWnd();
CSplitterWnd* pSplitter = &pMainWnd->m_wndSplitter;

CView* pOldActiveView = reinterpret_cast<CView*>(pSplitter->GetPane(row,col));
ASSERT(pOldActiveView != pNewView);

// set flag so that document will not be deleted when view is destroyed
m_bAutoDelete = FALSE;    
// Dettach existing view
RemoveView(pOldActiveView);
// set flag back to default 
m_bAutoDelete = TRUE;

// Set the child window ID of the active view to the ID of the corresponding
// pane. Set the child ID of the previously active view to some other ID.
::SetWindowLong(pOldActiveView->m_hWnd, GWL_ID, 0);
::SetWindowLong(pNewView->m_hWnd,GWL_ID,pSplitter->IdFromRowCol(row,col));

// Show the newly active view and hide the inactive view.
pNewView->ShowWindow(SW_SHOW);
pOldActiveView->ShowWindow(SW_HIDE);

// Attach new view
AddView(pNewView);

// Set active 
pSplitter->GetParentFrame()->SetActiveView(pNewView);
pSplitter->RecalcLayout(); 

return pOldActiveView;
}

我希望你能得到这个想法，否则就问。

Answer 2

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2列分离器，右侧有2行，一个向上，一个向下，另一个向左侧向上和向下？

CSplitterWnd在水平和垂直分离器之间翻转？

2 个答案: