我正在尝试搜索,我的网格显示了20条记录的结果。
如果我已应用allow paging true且页面大小为20
然后点击Grid中的第二页,我的整个网格正在刷新,再次以第一页显示整个网格。
如果记录为20且页面大小为10,我如何查看最近10条记录,从11到20
网格的客户端代码
<div id="divApplication" runat="server">
<asp:GridView ID="gvApplication"
runat="server"
AutoGenerateColumns="false"
AllowPaging="true"
AllowSorting="True"
AlternatingRowStyle-CssClass="alt"
PagerStyle-CssClass="pgr"
OnPageIndexChanging="OnPageIndexChanging"
CssClass="table table-bordered table-striped"
PageSize="10" Width="50%">
<Columns>
<asp:TemplateField HeaderText='Application' HeaderStyle-VerticalAlign="Middle">
<HeaderStyle HorizontalAlign="Center" VerticalAlign="Middle" CssClass="chkbox" />
<ItemTemplate>
<asp:Label ID="lblFirstName" runat="server"
att='<%#DataBinder.Eval(Container.DataItem,"ID")%>' Text='<%# SetLinkCodeApplication(Convert.ToInt64(DataBinder.Eval(Container.DataItem,"ID")),DataBinder.Eval(Container.DataItem,"Application").ToString()) %>'></asp:Label>
</ItemTemplate>
<ItemStyle Width="3%" HorizontalAlign="left" />
</asp:TemplateField>
</Columns>
</asp:GridView>
</div>
在C#上绑定我的网格服务器端代码
public void fncfillApplication()
{
try
{
DataSet ds = new DataSet();
ds.ReadXml(Server.MapPath("Application.xml"));
if (ds.Tables[0].Rows.Count != 0)
{
gvApplication.DataSource = ds;
gvApplication.DataBind();
}
}
catch (Exception ex)
{
ex.Message.ToString();
}
}
protected void OnPageIndexChanging(object sender, GridViewPageEventArgs e)
{
gvApplication.PageIndex = e.NewPageIndex;
this.fncfillApplication();
}
用于在编辑模式下绑定数据的Setlinkcode
public string SetLinkCodeApplication(Int64 sId, string sName)
{
string functionReturnValue = null;
try
{
functionReturnValue = "<a href=javascript:fncopenEditPopUpApplication(" + sId + ")>" + sName.Trim() + "</a>";
//return functionReturnValue;
}
catch (Exception ex)
{
throw;
}
return functionReturnValue;
}
我正在使用Xml Datasource来绑定数据
答案 0 :(得分:0)
我认为你应该使用
XDocument document = XDocument.Load(@"c:\users\administrator\documents\visual studio 2010\Projects\LINQtoXMLSelectApp\LINQtoXMLSelectApp\Employee.xml");
var query = from r in document.Descendants("Employee") where (int)r.Element("Age") > 27 select new
{
FirstName = r.Element("FirstName").Value, Age = r.Element("Age").Value };
GridView1.DataSource = query;
GridView1.DataBind();
答案 1 :(得分:0)
你的问题与我无关。它工作正常。我使用以下XML文件绑定到gridview。代码和HTML是一样的。
<?xml version="1.0" encoding="utf-8" ?>
<Customer>
<Customerinfo>
<Name>Vithal Wadje</Name>
<city>Mumbai</city>
<Address>Sion, Mumbai</Address>
</Customerinfo>
<Customerinfo>
<Name>D Sudhir Wadje</Name>
<city>Latur</city>
<Address>Latur</Address>
</Customerinfo>
<Customerinfo>
<Name>U D</Name>
<city>Mumbai</city>
<Address>DN,Road Mumbai</Address>
</Customerinfo>
<Customerinfo>
<Name>Anil Kumar</Name>
<city>Delhi</city>
<Address>Nehru House</Address>
</Customerinfo>
<Customerinfo>
<Name>Five</Name>
<city>Mumbai</city>
<Address>Sion, Mumbai</Address>
</Customerinfo>
<Customerinfo>
<Name>Six</Name>
<city>Mumbai</city>
<Address>Sion, Mumbai</Address>
</Customerinfo>
<Customerinfo>
<Name>Seven</Name>
<city>Mumbai</city>
<Address>Sion, Mumbai</Address>
</Customerinfo>
<Customerinfo>
<Name>Eight</Name>
<city>Mumbai</city>
<Address>Sion, Mumbai</Address>
</Customerinfo>
<Customerinfo>
<Name>Nine</Name>
<city>Mumbai</city>
<Address>Sion, Mumbai</Address>
</Customerinfo>
<Customerinfo>
<Name>Ten</Name>
<city>Mumbai</city>
<Address>Sion, Mumbai</Address>
</Customerinfo>
<Customerinfo>
<Name>Eleven</Name>
<city>Mumbai</city>
<Address>Sion, Mumbai</Address>
</Customerinfo>
<Customerinfo>
<Name>Twelve</Name>
<city>Mumbai</city>
<Address>Sion, Mumbai</Address>
</Customerinfo>
</Customer>
答案 2 :(得分:0)
我认为它可以帮助你
ds.Tables[0].Select("ID=1 AND ID2=3");