postgresql:在事件中分割时间段

时间:2017-07-27 15:02:03

标签: postgresql date period

我有一张乡村时期表。在某些情况下,某些国家属性(例如资本)在一段时间内的日期发生变化。在这里,我想将国家时期分为两个新时期,一个在此之前,一个在此之后。

示例:

Country |  start_date   |  end_date   | event_date 
   A    |  1960-01-01   | 1999-12-31  | 1994-07-20
   B    |  1926-01-01   | 1995-12-31  | NULL

期望的输出:

Country |  start_date   |  end_date   | event_date 
   A    |  1960-01-01   | 1994-07-19  | 1994-07-20
   A    |  1994-07-20   | 1999-12-31  | 1994-07-20
   B    |  1926-01-01   | 1995-12-31  | NULL

我考虑从这些行开始 generate_series

SELECT country, min(p1) as sdate1, max(p1) as sdate2,
min(p2) as sdate2, min(p2) as edate2 
  FROM 
   (SELECT country, 
    generate_series(start_date, (event_date-interval '1 day'), interval '1 day')::date as p1,
    generate_series(event_date, end_date, interval '1 day')::date as p2
   FROM table)t 
GROUP BY country

但这些似乎是低效率和混乱的方式。不幸的是,在编写函数方面我没有任何经验。关于如何解决这个问题的任何想法?

1 个答案:

答案 0 :(得分:1)

您可以改为UNION。这样就不会生成不必要的行

SELECT country, start_date, 
       CASE WHEN event_date BETWEEN start_date AND end_date 
            THEN event_date - 1 
            ELSE end_date
       END AS end_date, event_date
  FROM table1
 UNION ALL
SELECT country, event_date, end_date, event_date
  FROM table1
 WHERE event_date BETWEEN start_date AND end_date
 ORDER BY country, start_date, end_date, event_date

这是SQLFiddle演示

输出:

| country | start_date |   end_date | event_date |
|---------|------------|------------|------------|
|       A | 1960-01-01 | 1994-07-19 | 1994-07-20 |
|       A | 1994-07-20 | 1999-12-31 | 1994-07-20 |
|       B | 1926-01-01 | 1995-12-31 |     (null) |
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