Question

我正在从CSV文件中读取并创建了一个功能，将玩家与该文件分成2个列表：经验丰富且新鲜的玩家。

然后，我尝试创建另一个打印每个列表长度的函数。但是，当我运行我的脚本并调用2个函数时，Python会返回一个错误，指出第二个函数的变量未定义。不知道我做错了什么。

for row in range(0,len(shape.part() )):
    print row

结果：

import csv

with open('soccer_players.csv', newline='') as csvfile:
    players_reader = csv.DictReader(csvfile, delimiter=',')
    players = list(players_reader)

def separate(players):
    experienced = []
    fresh = []
    for player in players:
        if player['Soccer Experience'] == 'YES':
            experienced.append(player)
        else:
            fresh.append(player)

    return experienced, fresh


def countexperience (experienced, fresh):
    players_experience = len(experienced)
    players_fresh = len(fresh)

    print(players_experience)
    print(players_fresh)

while True:
    start = input("Want to start? (Y/n) ").lower()
    if start == "y":
        separate(players)
        countexperience(experienced, fresh)
        break
    elif start == "n":
        print("goodbye")
        break
    else:
        print("letter not accepted! Please write 'Y' to start or 'N' to exit!\n")

Answer 1

separate()中的局部变量未添加到当前范围，因此您需要将separate()的返回值分配给当前范围中的变量，例如：

experienced, fresh = separate(players)

注意：您可以使用任何您想要的名称，例如

e, f = separate(players)
countexperience(e, f)

您还可以使用tuple将函数调用中separate()的{{1}}返回值直接扩展为countexperience()，例如：

新函数不接受来自其他函数的返回值

1 个答案: