显示相邻不分页的下一行

Question

$MR = $mt->query('select dated, time1 from det where cus="name 10" and dated between "10-06-2017" and "20-06-2017" order by dated asc');
$MR -> execute();
$result = $MR -> fetchAll();

$i=1;
if ($i%2) {
            echo "<tr>";
                echo "<td style='width:20%'>";
                    echo $i;
                echo "</td>";
                echo "<td style='width:20%'>";
                    echo $row['dated'];
                echo "</td>";
                echo "<td></td>";
                echo "<td style='width:20%'>";
                    echo $row['time1'];
                echo "</td>";

            echo "</tr>";

        } else {
            echo "<tr>";
                echo "<td style='width:20%'>";
                     echo $i;
                echo "</td>";
                echo "<td style='width:20%'>";
                    echo $row['dated'];
                echo "</td>";
                echo "<td style='width:20%'>";
                    echo $row['time1'];
                echo "</td>";
                echo "<td></td>";
            echo "</tr>";

        }


        $i++;
    }

我使用PDO做了一个fetchAll（），我的表在执行$ i％2之后看起来如下，其中$ i是计数器。

+---------+----------+-------------+------------+
| no      | date     | time 1      | time 2     |
+---------+----------+-------------+------------+
+---------+----------+-------------+------------+
| 1       |12-06-2017| 05:00       |            |
+---------+----------+-------------+------------+
+---------+----------+-------------+------------+
|         |12-06-2017|             | 11:35      |
+---------+----------+-------------+------------+
+---------+----------+-------------+------------+
| 3       |13-06-2017| 04:4        |            |
+---------+----------+-------------+------------+
+---------+----------+-------------+------------+
|         |13-06-2017|             | 13:25      |
+---------+----------+-------------+------------+

如何在 05:00 附近获得值 11:35 ，对于其他行也是如此。有超过100行。我可以显示time1的下一条记录吗？

分页不是我要找的东西。

[UPDATE]

预期输出

+---------+----------+-------------+------------+
| no      | date     | time 1      | time 2     |
+---------+----------+-------------+------------+
+---------+----------+-------------+------------+
| 1       |12-06-2017| 05:00       | 11:35      |
+---------+----------+-------------+------------+
+---------+----------+-------------+------------+
| 2       |13-06-2017| 04:4        |  13:25     |
+---------+----------+-------------+------------+

Answer 1

试试这个

select dated,
Group_concat( time1 separator ',') as time1
from det 
where 
cus="name 10" and 
dated between "10-06-2017" and "20-06-2017"
group by dated
order by dated asc 

它将以“

”的形式发出

dated      | time1
12-06-2017 | 05:00,11:35 

修改： -
使用此代码创建表行

$times=explode(',', $row['time1']);
$time1=(isset($times[0]))?$times[0]:'';
$time2=(isset($times[1]))?$times[1]:'';
echo "<tr>";
echo "<td style='width:20%'>";
echo $i;
echo "</td>";
echo "<td style='width:20%'>";
echo $row['dated'];
echo "</td>";
echo "<td></td>";
echo "<td style='width:20%'>";
echo $row['time1'];
echo "</td>";