如何将JSONobject转换为JSonArray ......？

Question

我有回复

{

"p1":{
"date":"Sat, 29 Jul 2017 03:31:43 GMT",
"plan_id":"5c4c6548-38cb-4dbb-b7a3-a3f260fb8532",
"plan_name":"Ultra50",
"pulse":1,
"tarrif":1,
"validity":30
},
"p2":{
"date":"Sat, 29 Jul 2017 03:31:43 GMT",
"plan_id":"5c4c6548-38cb-4dbb-b7a3-a3f260fb8532",
"plan_name":"Ultra50",
"pulse":1,
"tarrif":1,
"validity":30
}
}

这是我的代码

 Response.Listener<JSONObject> responseListener = new Response.Listener<JSONObject>() {

        @Override
        public void onResponse(JSONObject response) {
            try {

                JSONObject plan=response.getJSONObject("p1");
                Iterator x=plan.keys();
                JSONArray jsonElements=new JSONArray();
                while (x.hasNext()){
                    String key=(String) x.next();
                    jsonElements.put(plan.get(key));
                    Log.e(TAG, "onResponse: "+key );

                }
                Log.d(TAG, "onResponse: "+jsonElements.toString());
            } catch (JSONException e) {
                e.printStackTrace();
            }

如何在一个JsonArray中转换p1，p2，p3？

Answer 1

您应该使用 ITERATOR 。

  

它用于逐个遍历集合对象元素。

 Iterator  iteratorObj = response.keys();
        while (iteratorObj.hasNext())
        {
            String getKEY = (String)iteratorObj.next();
            System.out.println("Key: " + Key + "------>" + getKEY); // p1,p2
        }

Answer 2

1. 将对象转换为字符串
2. 将First {更改为[和last} to]
3. 将字符串转换为JSONArray

String res = response.toString().trim();
        res = res.replaceFirst("\{","]");
        res = res.substring(0,res.length()-1) + "]";
        try {
                   JSONArray arr = new JSONArray(res.toString());
        }catch (JSONException j)
        {

        }

Answer 3

Iterator planKeys = response.keys();
{
    JSONArray jsonElements=new JSONArray();
    while(planKeys.hasNext()){
        String key = (String) planKeys.next();
        JSONObject plan = response.getJSONObject(key);
        Iterator x=plan.keys();
        while (x.hasNext()){
            String key=(String) x.next();
            jsonElements.put(plan.get(key));
            Log.e(TAG, "onResponse: "+key );

        }
    }
}

JSONObject plan=response.getJSONObject("p1");