使用不同拆分从字符串创建多个列表

时间:2017-08-03 05:22:44

标签: c# visual-studio

这是示例代码。

我的字符串包含行星名称,顺序和颜色,由spacesNewLines分隔。

我不想修改字符串来改变结果。

我想从字符串中创建3个列表,OrderNameColor

| Order      | Name       | Color      |
|------------|------------|------------|
| First      | Mercury    | Gray       |
| Second     | Venus      | Yellow     |
| Third      | Earth      | Blue       |
| Fourth     | Mars       | Red        |

这将从List创建string,由NewLine分割。

string planets = "First Mercury Gray" 
                + Environment.NewLine 
                + "Second Venus Yellow"
                + Environment.NewLine
                + "Third Earth Blue"
                + Environment.NewLine 
                + "Fourth Mars Red"
                + Environment.NewLine;


List<string> PlanetOrder = planets.Split(
               new[] { Environment.NewLine }, StringSplitOptions.None).ToList();   

List<string> PlanetName = planets.Split(
               new[] { Environment.NewLine }, StringSplitOptions.None).ToList();

List<string> PlanetColor = planets.Split(
               new[] { Environment.NewLine }, StringSplitOptions.None).ToList();

但在每一行中,如何按space拆分并选择单词[1]订单,[2]名称,[3]颜色?

planets.Split(' ')[2]; //Name

3 个答案:

答案 0 :(得分:6)

您可以执行以下操作。首先按$servername = "localhost"; $dbName = XXXXXXXXX $dbUser = XXXXXXXXX; $dbPass = XXXXXXXXX; $conn = new PDO("mysql:host=$servername;dbname=XXXXXXXXX", $dbUser, $dbPass); $delimiter = "**"; $query = "SELECT * FROM `images` WHERE `portfolio_id` = 'X' AND `image_status` = 'X' ORDER BY rand()"; $conn->query($query); while($row = mysql_fetch_array($query)){ $sVal = substr($row['image_full'],0); $nString = $nString.$delimiter.$sVal; } 拆分字符串,然后将结果的每一行拆分为Environment.NewLine,并将项目添加到不同的列表中。

space

答案 1 :(得分:2)

LINQ方法:

public enum PlanetColumn
{
    Order = 0,
    Name = 1,
    Color = 2
}

string planets = "First Mercury Gray" 
            + Environment.NewLine 
            + "Second Venus Yellow"
            + Environment.NewLine
            + "Third Earth Blue"
            + Environment.NewLine 
            + "Fourth Mars Red"
            + Environment.NewLine;

var lookup = planets
    .Split(new[] { Environment.NewLine }, StringSplitOptions.RemoveEmptyEntries)
    .SelectMany(p => p.Trim().Split(' ').Select((value, colIndex) => new { Column = (PlanetColumn) colIndex, Value = value} ))
    .ToLookup(prop => prop.Column, prop => prop.Value);

var planetOrders = lookup[PlanetColumn.Order].ToList();
var planetNames = lookup[PlanetColumn.Name].ToList();
var planetColors = lookup[PlanetColumn.Color].ToList();

注意:我添加enum声明只是因为它看起来更干净,您可以直接使用整数值(并使用lookup[0]lookup[1] ,和lookup[2]

答案 2 :(得分:1)

或与Linq foreach:

        List<string> planetOrder = new List<string>();
        List<string> planetName = new List<string>();
        List<string> planetColor = new List<string>();
       planets.Split(new[] { Environment.NewLine }, StringSplitOptions.RemoveEmptyEntries).ToList().ForEach(p =>
        {
            planetOrder.Add(p.Split(new[] { ' ' })[0]);
            planetName.Add(p.Split(new[] { ' ' })[1]);
            planetColor.Add(p.Split(new[] { ' ' })[2]);
        });
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