Question

我有api_gateway的terraform脚本，工作正常。我有很多模板重复。我想使用"data" "template_file"提取所有模板。

工作解决方案：

resource "aws_api_gateway_integration_response" "ApiResponse" {
   //something goes here
     response_parameters  = {
        "method.response.header.Access-Control-Allow-Headers" = "'Content-Type,X-Amz-Date,Authorization,X-Api-Key,X-Amz-Security-Token'"
        "method.response.header.Access-Control-Allow-Methods" = "'GET,DELETE,PUT,OPTIONS'"
        "method.response.header.Access-Control-Allow-Origin" = "'*'"
      }
}

重构后：

resource "aws_api_gateway_integration_response" "ApiResponse" {
   //something goes here
     response_parameters = "${data.template_file.response_parameters.template}"
}

data "template_file" "response_parameters" {
   template = "${file("${path.module}/response_parameters.tptl")}"
}

response_parameters.tptl：

{
    "method.response.header.Access-Control-Allow-Headers" = "'Content-Type,X-Amz-Date,Authorization,X-Api-Key,X-Amz-Security-Token'"
    "method.response.header.Access-Control-Allow-Methods" = "'GET,DELETE,PUT,OPTIONS'"
    "method.response.header.Access-Control-Allow-Origin" = "'*'"
}

错误：

* aws_api_gateway_integration_response.ApiResponse: response_parameters: should be a map

由于响应参数对于我的所有aws_api_gateway_integration_response都是通用的，我想拥有一个通用模板并在所有资源中重用。

为什么我会收到此错误？

Answer 1

它使用variable类型map代替"data" "template_file"

resource "aws_api_gateway_integration_response" "ApiResponse" {
//something goes here 
   response_parameters = "${var.integration_response_parameters}"
}

variable "integration_response_parameters" {
   type = "map"
   default = {
        method.response.header.Access-Control-Allow-Headers = "'Content-Type,X-Amz-Date,Authorization,X-Api-Key,X-Amz-Security-Token'"
        method.response.header.Access-Control-Allow-Methods = "'GET,OPTIONS'"
        method.response.header.Access-Control-Allow-Origin = "'*'"
     }
}

Terraform - response_parameters：应该是一张地图

1 个答案: