Question

有哪些方法可以使此代码更清晰，更高效？我是python的新手，我不想开始养成坏习惯！谢谢你的帮助！

    store = input('Name of store: ')
food = input('Type of food served: ')
serverName = 'Will'
drinkPrice = ''
foodPrice = ''
drink = input('Hello! My name is {0} and I will be your server today! What can I get you to drink?: '.format(serverName))
if drink == "Water":
    drinkPrice = 1
else :
    if drink == "Coke":
    drinkPrice = 2
else :
    if drink == "Beer":
    drinkPrice = 5
else :
    print("The item you are trying to order is not on the menu!")
drink = input("What else would you like to drink?:")
food = input('What will you be ordering tonight?: ')
if food == "Steak":
    foodPrice = 25
else :
    if food == "Pizza":
    foodPrice = 10
else :
    if food == "Salad":
    foodPrice = 5
else :
    print("The item that you are trying to order is not on the menu!")
totalPrice = str(drinkPrice) + str(foodPrice)
print('Thanks for eating at {0} and ordering {1} ! Server name: {2} Price total: {3}'.format(store, food, serverName, totalPrice))

Answer 1

为什么第一行缩进？您也不需要将服务器的名称放在变量中 - 它会添加不必要的行。只需将其包含在服务器名称（Will）所在的字符串中。您也可以尝试将饮料及其价格放入字典中。另外你为什么要这样做：str(drinkPrice) + str(foodPrice) 为什么您将drinkPrice和foodPrice转换为字符串，何时应该保留为数字？这只会将它们作为字符串连接在一起，并会导致逻辑错误。所以说饮料的价格是5，食品价格是4，你的程序将使总价格变为54，当它应该是9。

如何提高效率？

1 个答案: