sorry... my English is not very good... so i didn't know How to ask this question... please just read so u can understand what i want... I have a def which takes a dictionary:
{'John':30.370, 'Mike':84.5, 'Sara':97.55, 'Frank': 75.990}
And i wanna return this:
Sara 97.55
Mike 84.50
Frank 75.99
John 30.37
But My solution don't return this! My solution:
def formatted(a):
s=''
for i in a:
d='{0:<10s}{1:>6.2f}\n'.format(i, a[i])
s=s+d
s=s.rstrip()
return s
a={'John':30.370, 'Mike':84.5, 'Sara':97.55, 'Frank': 75.990}
print (formatted(a))
it returns:
John 30.37
Mike 84.50
Sara 97.55
Frank 75.99
I should sort these numbers...But i Have no idea How to do that! Anybody can help??
答案 0 :(得分:1)
>>> d = {'John':30.370, 'Mike':84.5, 'Sara':97.55, 'Frank': 75.990}
>>> b = sorted(d.items(), key=lambda x: x[1])
>>> print b
[('John', 30.37), ('Frank', 75.99), ('Mike', 84.5), ('Sara', 97.55)]
for reverse
>>> c = sorted(d.items(), key=lambda x: x[1] ,reverse=True)
>>> print c
[('Sara', 97.55), ('Mike', 84.5), ('Frank', 75.99), ('John', 30.37)]
for print use :
d = collections.OrderedDict(dict(c)) # c is upder dict
for i, v in d.items():
_dict_pair='{0:<10s}{1:>6.2f}\n'.format(i, v)
print(_dict_pair)
答案 1 :(得分:0)
You need to sort
the dictionary on values
using sorted
and [operator.itemgetter][1]
.
In [100]: _dict = collections.OrderedDict(sorted(d.items(), key=operator.itemgetter(1), reverse=True)) # d is your dictinory
In [101]: _dict
Out[101]:
OrderedDict([('Sara', 97.55),
('Mike', 84.5),
('Frank', 75.99),
('John', 30.37)])
Then you need to use collections.OrderedDict
as dictionaries
are hash key pair.
for i, v in _dict.items():
d='{0:<10s}{1:>6.2f}\n'.format(i, v)
print(d)
Sara 97.55
Mike 84.50
Frank 75.99
John 30.37
答案 2 :(得分:0)
In one line :
d = {'John': 30.370, 'Mike': 84.5, 'Sara': 97.55, 'Frank': 75.990}
print(
"\n".join(
'{0:<10s}{1:>6.2f}'.format(k, v) for k, v in sorted(d.items(), key=lambda x: x[1], reverse=True)
)
)
Sara 97.55
Mike 84.50
Frank 75.99
John 30.37
Explanation :
sorted(d.items(), key=lambda x: x[1], reverse=True)
=> sorted method in python"\n".join()
to regroup and format everybody in one string separated by \n
=> join method