Question

我需要制作一个密码重置程序，让用户输入两次新密码，以便计算机知道用户在输入新密码时没有犯任何错误。它也应该只接受密码，如果它是八个字符或更少，并包括小写和大写字母。这是我到目前为止所做的：

import os
import time

def main():
    while True:
        PassWord = input ("Enter Password: ")

          for c in s:
              if c.islower():
                print c
          Password == :
            time.sleep(1)
            print ("Login successful!")
            logged()

        else:
            print ("Please try again")

def logged():
    time.sleep(1)
    print ("Welcome to ----")


main()

Answer 1

您的程序中存在许多语法错误。值得重新考虑核心逻辑。

import os
import time
import getpass

def logged():
    time.sleep(1)
    print ("Welcome to ----")


def checklower(pw):
    for c in pw:
        if c.islower():
            return True

def checkupper(pw):
    for c in pw:
        if c.isupper():
            return True

def main():
    while True:  # having this loop because you have it too
        password_1 = getpass.getpass()
        print "One more time"
        password_2 = getpass.getpass()
        if (password_1 != password_2) or not (checkupper(password_1)) or not (checklower(password_2)) or not (len(password_1) >= 8):
            print "Please try again"
            continue
        else:
            logged()
            break

main()

这是您需要的超级快速和肮脏的实现

Answer 2

我不确定哪个身份验证系统允许八个或更少的字符，但当然，我们可以让它工作。

在处理密码时，您不应该使用普通input。在这种情况下，任何看着你肩膀的人都可以轻松获得你的密码。您应该使用getpass代替，这是标准库的一部分。函数将检查密码是否满足条件并返回布尔值。这不是最佳实现，但它适用于此问题。希望这会有所帮助。

from getpass import getpass


def check_password(password):
    if len(password) > 9:
        return False
    for character in password:
        if character.isupper():
            return True


def main():
    while True:
        password = getpass()
        if password == getpass():
            if check_password(password):
                print('Successfully logged in.')
                break
        else:
            print('Try again!')

if __name__ == '__main__':
    main()

Answer 3

import time
import re

password=''
password2=''
def validate_password(password):
      if len(password) <8:
            print 'returning 1'
            return 1
      if not re.search('[0-9]',password):
            return 2
      if not re.search('[a-z]',password):
            return 3
      if not re.search('[A-Z]',password):
            return 4
      return 0

def check_password(password,password2):
      if password==password2:
            return True
      else:
            return False

def get_password():
      password=raw_input('Enter password:')
      flag=validate_password(password)
      if flag==0:
            password2=raw_input('Re-Enter Password:')
            flag2=check_password(password,password2)
            if flag2==True:
                  return True
            else:
                  print 'Passwords do not match!!'
                  return False
      elif flag==1:
            print 'Password must be of 8 characters'
            return False
      elif flag==2:
            print 'Password must contain a number'
            return False
      elif flag==3:
            print 'Password must include a small letter'
            return False
      elif flag==4:
            print 'Password must also include a small letter'
            return False
def logged():
      print 'Logging in...'
      time.sleep(5)
      print 'Successfully logged in'

def main():
      flag=get_password()
      if flag==True:
            logged()
      else:
            while True:
##                  print ''
                  get_password()

main()

重置密码python程序

3 个答案: