Angular:如何获取路由器插座的组件实例

时间:2017-08-09 10:02:24

标签: angular angular-ui-router angular2-routing angular-routing

HTML:

<router-outlet></router-outlet>

成分:

@Component({
      selector: 'xx',
      templateUrl: './xx.html',
      styleUrls: ['./xx.css'],
      providers: [ RouterOutlet]
    })
    export class AppComponent {
    constructor(private routeroutlet: RouterOutlet){ }
    getref() {
     console.log(this.routeroutlet);
     console.log('refresh', this.routeroutlet.component);
    }
}

我收到此错误

core.es5.js:1224 ERROR Error: Outlet is not activated
    at RouterOutlet.get [as component] (router.es5.js:5449)
    at AppComponent.onRefreshscrum (app.component.ts:343)
    at Object.eval [as handleEvent] (AppComponent.ngfactory.js:111)
    at Object.handleEvent (core.es5.js:12251)
    at Object.handleEvent (core.es5.js:12975)
    at dispatchEvent (core.es5.js:8863)
    at eval (core.es5.js:11025)
    at SafeSubscriber.schedulerFn [as _next] (core.es5.js:3851)
    at SafeSubscriber.__tryOrUnsub (Subscriber.js:223)
    at SafeSubscriber.next (Subscriber.js:172)

控制台结果:( this.routeroutlet)

RouterOutlet {
parentContexts: ChildrenOutletContexts, 
location: null, 
resolver: CodegenComponentFactoryResolver, 
changeDetector: ViewRef_, 
activated: null, …}activateEvents: EventEmitter {_isScalar: false, observers: Array(0), 
closed: false, 
isStopped: false, 
hasError: false, 
…}
closed: false
hasError: false
isStopped: false
observers: []thrown
Error: null
__isAsync: false
_isScalar: false
__proto__: Subject
activated: null
activatedRoute: (...)activatedRouteData: (...)changeDetector: ViewRef_ {_view: {…}, _viewContainerRef: null, _appRef: null}
component: [Exception: Error: Outlet is not activated
    at RouterOutlet.get [as component] (webpack:///./~/@angular/router/@angular/router.es5.js?:5449:23)
    at RouterOutlet.remoteFunction (<anonymous>:2:26)]deactivateEvents: EventEmitter {_isScalar: false, observers: Array(0), 
closed: false, 
isStopped: false, 
hasError: false, …}
isActivated: (...)location: nulllocationFactoryResolver: (...)l
ocationInjector: (...)name: "primary"
parentContexts: ChildrenOutletContexts {contexts: Map(1)}resolver: CodegenComponentFactoryResolver {_parent: null, _ngModule: NgModuleRef_, _factories: Map(52)}_activatedRoute: null__proto__: ObjectactivateWith: ƒ (activatedRoute, resolver)activatedRoute: (...)activatedRouteData: (...)attach: ƒ (ref, activatedRoute)component: (...)deactivate: ƒ ()detach: ƒ ()isActivated: (...)locationFactoryResolver: (...)locationInjector: (...)ngOnDestroy: ƒ ()ngOnInit: ƒ ()arguments: (...)caller: (...)length: 0name: ""prototype: {constructor: ƒ}__proto__: ƒ ()[[FunctionLocation]]: router.es5.js:5400[[Scopes]]: Scopes[3]constructor: ƒ RouterOutlet(parentContexts, location, resolver, name, changeDetector)get activatedRoute: ƒ ()get activatedRouteData: ƒ ()get component: ƒ ()get isActivated: ƒ ()get locationFactoryResolver: ƒ ()get locationInjector: ƒ ()__proto__: Object

以上控制台结果用于控制台路由器对象。

我想访问在router-outlet中呈现的组件实例。我如何访问组件的实例?

3 个答案:

答案 0 :(得分:13)

请勿尝试将RouterOutlet用作提供程序。而是将(activate)属性添加到router-outlet标记中,如下所示:

<router-outlet (activate)="onRouterOutletActivate($event)"></router-outlet>

然后在包含router-outlet元素(您的AppComponent类)的组件中,您应该实现onRouterActivate方法:

public onRouterOutletActivate(event : any) {
    console.log(event);
}

将为您提供event参数中的路由组件实例,在此示例中写入Web控制台。

答案 1 :(得分:0)

为了获得 RouterOutlet 实例,以下对我有用..

<router-outlet
  #foo="outlet"
></router-outlet>
@ViewChild( 'foo' )
foo: RouterOutlet;

https://angular.io/api/router/RouterOutlet#template-variable-references

答案 2 :(得分:-1)

如果要使用DOM元素,则需要获取router-outlet的DOM元素,然后在activate()事件之后获取下一个同级

const sib = this.element.nativeElement.nextSibling;

有多种获取router-outlet元素的方法,例如使用ViewChild

另一种方法是将伪指令应用于router-outlet。我将这种方法用于a directive that adds classes to the component DOM element