Question

我有一个下拉列表，其中包含来自数据库的客户名称。我希望这些值与我的'href'属性相关联。我该怎么做？

 <select class="feedback-input" id="customer_selecter" name="customerName"> 
            <option >Select customer</option>
            <?php foreach ($customers as $row): ?>
                <a href="<?php echo base_url() . "index.php/edit/show_customer_id/" . $row->customerID; ?>">
            <?php echo '<option value="'.$row->customerID.'">'.$row->customerName.'</option>'; ?></a>
            <?php endforeach; ?>
        </select>

Answer 1

试试这个：

<select class="feedback-input" id="customer_selecter" name="customerName"> 
    <option >Select customer</option>
    <?php foreach ($customers as $row): ?>
        <a href="<?php echo base_url() . 'index.php/edit/show_customer_id/' . $row->customerID; ?>">
            <option value="<?php echo $row->customerID; ?>"><?php echo $row->customerName; ?></option>
        </a>
    <?php endforeach; ?>
 </select>

但这不是一个有效的HTML，因为你在<a>代码中使用了<select>代码，请尝试使用javascript代替这样做：

 <select class="feedback-input" id="customer_selecter" name="customerName" onchange="location = this.value;"> 
    <option >Select customer</option>
    <?php foreach ($customers as $row): ?>
        <option value="<?php echo base_url() . 'index.php/edit/show_customer_id/' . $row->customerID; ?>"><?php echo $row->customerName; ?></option>
    <?php endforeach; ?>
 </select>

用php链接下拉列表

1 个答案: