SQL存储过程使用Cursor更新表

时间:2010-12-30 11:11:25

标签: sql oracle oracle10g cursor ora-00942

我正在尝试使用存储过程更新表,但它发出错误,请解释原因。这是代码。

CREATE OR REPLACE Procedure UpdateItem
   ( ITEM_TYPE_NAME IN varchar2 )
IS
    V_TABLE_NAME    VARCHAR2(100);
    V_R_TABLE_NAME  VARCHAR2(100);
    V_SQL_STMT     VARCHAR2(1000);

   cursor c1 is
    select C.RTARGETITEMID ||'#'||C.VERSIONID||'#'||trim(p.CREATEUSERID)||'#bsacm#CBR.CLLCT001# #/icmrm/ICMResourceManager#727665642020202020202020#2509.000000#9080#1#ICMNLSDB# #201#1#' as ITEM_REF, C.ITEMID as ITEM_ID 
    from  V_TABLE_NAME  C, V_R_TABLE_NAME R 
    where C.TIEFLAG = 0 and C.ITEMID=R.ITEMID;


BEGIN

select TABLE_NAME into V_TABLE_NAME 
from user_indexes 
where INDEX_NAME = (SELECT distinct c.INDEXNAME
                    FROM ICMSTNLSKEYWORDS k, ICMSTCOMPDEFS d, ICMSTTEXTINDEXES c
                    WHERE k.KEYWORDCLASS = 2 AND k.KEYWORDCODE = d.ITEMTYPEID AND d.COMPONENTTYPEID = c.COMPONENTTYPEID AND k.KEYWORDNAME = ITEM_TYPE_NAME);

select TABLE_NAME into V_R_TABLE_NAME 
from user_constraints 
where CONSTRAINT_NAME in (select distinct R_CONSTRAINT_NAME 
                          from user_constraints 
                          where TABLE_NAME in (select TABLE_NAME 
                                              from user_indexes 
                                              where INDEX_NAME = (SELECT distinct c.INDEXNAME
                                                                  FROM ICMSTNLSKEYWORDS k, ICMSTCOMPDEFS d, ICMSTTEXTINDEXES c
                                                                  WHERE k.KEYWORDCLASS = 2 AND k.KEYWORDCODE = d.ITEMTYPEID AND d.COMPONENTTYPEID = c.COMPONENTTYPEID AND k.KEYWORDNAME=ITEM_TYPE_NAME)));

open c1;
fetch c1 into V_SQL_STMT;
EXECUTE IMMEDIATE 'UPDATE V_TABLE_NAME set TIEFLAG = ''1'',TIEREF = c1.ITEM_REF WHERE ITEMID = ITEM.ITEM_ID';

commit;

close c1;

EXCEPTION
WHEN OTHERS THEN
      raise_application_error(-20001,'An error was encountered - '||SQLCODE||' -ERROR- '||SQLERRM);
END;

这就是错误:

  

错误(9,5):PL / SQL:SQL语句   忽略错误(10,28):PL / SQL:   ORA-00942:表或视图没有   存在

1 个答案:

答案 0 :(得分:0)

由于V_TABLE_NAME是变量,您需要在字符串中连接变量。您的方式假定您的系统中有一个名为* V_TABLE_NAME *的表。

据我所知,你需要更改一行:

EXECUTE IMMEDIATE 'UPDATE V_TABLE_NAME set TIEFLAG = ''1'',TIEREF = c1.ITEM_REF WHERE ITEMID = ITEM.ITEM_ID';

EXECUTE IMMEDIATE 'UPDATE '||V_TABLE_NAME||' set TIEFLAG = ''1'',TIEREF = c1.ITEM_REF WHERE ITEMID = ITEM.ITEM_ID';