Question

我有以下代码：

$BuildDetails = Get-Content "d:\BuildDetails.txt"

[regex]$BuildDetailsRY = '\bRY:\s+\K\S+'
[regex]$BuildDetailsRoY = '\bRoY:\s+\K\S+'
[regex]$BuildDetailsSP = '\bSP:\s+\K\S+'
[regex]$BuildDetailsRC = '\bRC:\s+\K\S+'
[regex]$BuildDetailsBranch = '\bBranch:\s+\K\S+'

$ReleaseYear = $BuildDetails | Select-String $BuildDetailsRY -AllMatches | Foreach-Object {$_.Matches} | 
       Foreach-Object {$_.Groups[2].Value}

Write-Host Release Year = $ReleaseYear

当我运行它时，我收到以下错误：无法转换价值＆＃34; \ bSP：\ s + \ K \ S +＆＃34;输入＆＃34; System.Text.RegularExpressions.Regex＆＃34;。错误：＆＃34;解析＆＃34; \ bSP：\ s + \ K \ S +＆＃34; - 无法识别的转义序列\ K。＆＃34;

这是它正在查找的文本文件。

RY: 17
RoY: 2
SP: 0
RC: 1
Branch: $/Release/17.2.x

我希望REGEX做的是在标题后找到数据，例如17

Answer 1

我最终找到了一个更好的方法：

$BuildDetails = Get-Content "D:\BuildDetails.txt"

[regex]$BuildDetailsRY = '(?<=RY: ).*?(?=\s)'
[regex]$BuildDetailsRoY = '(?<=RoY: ).*?(?=\s)'
[regex]$BuildDetailsSP = '(?<=SP: ).*?(?=\s)'
[regex]$BuildDetailsRC = '(?<=RC: ).*?(?=\s)'
[regex]$BuildDetailsBranch = '(?<=Branch: ).*'

$ReleaseYear = [regex]::matches($BuildDetails, $BuildDetailsRY)
$ReleaseofYear = [regex]::matches($BuildDetails, $BuildDetailsRoY)
$SP = [regex]::matches($BuildDetails, $BuildDetailsSP)
$RC = [regex]::matches($BuildDetails, $BuildDetailsRC)
$Branch = [regex]::matches($BuildDetails, $BuildDetailsBranch)

PowerShell：无法识别的转义序列

1 个答案: