Question

我会读取文件内容作为我程序的输入。

我将它存储在一个字符串中并将其拆分为2个字符串。

File file = new File("question.txt");
PrintWriter pw = new PrintWriter(file);
pw.write("81 : (1,53.38,$45) (2,88.62,$98) (3,78.48,$3) (4,72.30,$76) (5,30.18,$9) (6,46.34,$48)");
pw.close();
BufferedReader br = new BufferedReader(new FileReader(file));
String line = br.readLine();
Map<Integer, Object> map = new HashMap<Integer, Object>();
int i = 0;
Demo d = new Demo();
String[] part = line.split(":");
String part1 = part[0].trim();
String part2 = part[1].trim();

输入： 81 : (1,53.38,$45) (2,88.62,$98) (3,78.48,$3) (4,72.30,$76) (5,30.18,$9) (6,46.34,$48)

输出

totalWeight = 81;
index[] = {1,2,3,4,5,6}; 
weight[] = {53.38,88.62,78.48,72.30,30.18,46.34};  
value[] = {45,98,3,76,9,48};

第二个String在括号内包含3个值。第一个数字是“索引”，第二个数字是“重量”，第三个数字是“价值” 如何拆分并将其存储到3个不同的阵列中？

我知道这样做的一种方法是将其解析为具有3个数组并为其赋值的类的对象。
但有没有更好的方法呢？

Answer 1

String[] part2 = part[1].replace("(", "").trim().split(")");
List<String> indices = new ArrayList<String>();
List<String> weights= new ArrayList<String>();
List<String> values = new ArrayList<String>();

for (String s : part2)
{
   String item = s.split(",");
   indices.add(item[0]);
   weights.add(item[1]);
   values.add(item[2]);
}

// to get them as arrays
String[] allWeightsArray = weights.toArray(new String[]); ...

Answer 2

使用此代码以此格式解析字符串：

String[] structured = part2.replaceAll("[()]", "").split(" ");

List<String> indexes = new ArrayList<>();
List<String> weights = new ArrayList<>();
List<String> values = new ArrayList<>();

for (String elem : structured) {
    String[] parsed = elem.split(",");
    indexes.add(parsed[0]);
    weights.add(parsed[1]);
    values.add(parsed[2]);
}

Answer 3

使用split方法按[$?+\$]+\s+

分割字符串

String x = part[1].trim(); 
String[] items = x.split("[\\(?+\\)]+\\s+");
List<String> indexs = new ArrayList<>();
List<String> wights = new ArrayList<>();
List<String> values = new ArrayList<>();
for(String item : items)
{
    item = item.replace("(" , "").replace(")" , "").trim();
    String[] partItems = item.split(",");
    indexs.add(partItems[0]);
    wights.add(partItems[1]);
    values.add(partItems[2]);
}

System.out.println(Arrays.toString(indexs.toArray()));
System.out.println(Arrays.toString(wights.toArray()));
System.out.println(Arrays.toString(values.toArray()));

输出

[1, 2, 3, 4, 5, 6]
[53.38, 88.62, 78.48, 72.30, 30.18, 46.34]
[$45, $98, $3, $76, $9, $48]

Answer 4

您可以使用以下模式解决您的问题：

String str = "81 : (1,53.38,$45) (2,88.62,$98) (3,78.48,$3) "
    + "(4,72.30,$76) (5,30.18,$9) (6,46.34,$48)";

String regex = "\\((\\d+),(\\d+\\.\\d+),([^\\d](\\d+))\\)";
Pattern pattern = Pattern.compile(regex);
Matcher matcher = pattern.matcher(str);
double totalWeight = Double.parseDouble(str.replaceAll("^(\\d+).*", "$1"));
List<Integer> indexes = new ArrayList<>();
List<Double> weights = new ArrayList<>();
List<Integer> valuess = new ArrayList<>();

while (matcher.find()) {  
    indexes.add(Integer.parseInt(matcher.group(1)));
    weights.add(Double.parseDouble(matcher.group(2)));
    valuess.add(Integer.parseInt(matcher.group(4)));
}

System.out.println(totalWeight);// 81.0
System.out.println(indexes);    // [1, 2, 3, 4, 5, 6]
System.out.println(weights);    // [53.38, 88.62, 78.48, 72.3, 30.18, 46.34]
System.out.println(valuess);    // [45, 98, 3, 76, 9, 48]

总权重是输入中的第一个数字，您可以使用replaceAll然后解析输入Double.parseDouble(str.replaceAll("^(\\d+).*", "$1"));
要获取其他信息，您可以使用此正则表达式$(\d+),(\d+\.\d+),([^\d](\d+))$（regex demo），它可以匹配两个()之间的三个不同数字，在您的情况下，您有很多结果可以使用模式。

从文件中读取并将它们解析为不同的数组

4 个答案: