我是MATLAB的新手。我使用imhist函数计算了25个直方图,这是通过使用for循环将图像细分为25个块(1block = 1个组合图)而创建的。如何在同一图表上连接这些直方图以制作一个直方图,例如,第一个块的直方图在x轴上从0到255延伸,第二个块的直方图从256延伸到511,依此类推,直到第25个街区。我怎么能这样做?
我找到了这样的解决方案How to concatenate 3 histograms on the same graph in Matlab,但我的问题是我使用for循环计算了所有25个直方图,我不知道应该传递什么变量,这样我就可以连接1长的所有直方图直方图,因为我想要它。我也找到了类似的例子,但它是在python Concatenate multiple histograms in matplotlib
中这就是我所做的:
%declare variable
B=12; %B represent the block size
overlapp=3; %overlapping block is slid by 3 pixels along the image
nob=0; %no of blocks
%get input from grayscale image
gray_path = 'D:\gray_image_folder\*.png';
total_gray_images=dir(gray_path);
for noOfGRAYimage = 1:length(total_gray_images)
% Specify images names with full path and extension
grayfilename=strcat('D:\gray_image_folder\', total_gray_images(noOfGRAYimage).name);
grayImage = imread(grayfilename);% Read gray images
[r, c, p]=size(grayImage);
for i=1:overlapp:(r-B)+1;
% fprintf('i = %d\n', i);
% numberofblock = sprintf('%s_%d','block',nob)
for j=1:overlapp:(c-B)+1;
% fprintf('j = %d\n', j);
nob=nob+1;
fy_mad(nob).block=grayImage(i:i+B-1,j:j+B-1); %partition (12x12) of blocks
fy_mad(nob).position=[i j];
fy_mad(nob).index=nob;
[rb, cb]=size(fy_mad(nob).block); %[12,12]
localBinaryPatternImage = fy_mad(nob).block;
%call function LBP
LBP_centre = LBP (localBinaryPatternImage);
figure;imhist(uint8(LBP_centre)) %histogram for each block
% How to concatenate all histograms?
%////
end
end
end
我根据@crazyGamer
尝试了这个%get input from grayscale image
gray_path = 'D:\gray_image_folder\*.png';
total_gray_images=dir(gray_path);
allCounts = []
allBinLocs = []
for noOfGRAYimage = 1:length(total_gray_images)
% Specify images names with full path and extension
grayfilename=strcat('D:\gray_image_folder\', total_gray_images(noOfGRAYimage).name, total_gray_images(noOfGRAYimage).name);
grayImage = imread(grayfilename);% Read gray images
[r, c, p]=size(grayImage);
for i=1:overlapp:(r-B)+1;
for j=1:overlapp:(c-B)+1;
nob=nob+1;
fy_mad(nob).block=grayImage(i:i+B-1,j:j+B-1);
fy_mad(nob).position=[i j];
fy_mad(nob).index=nob; %number of blocks
[rb, cb]=size(fy_mad(nob).block);
localBinaryPatternImage = fy_mad(nob).block;
%call function LBP
LBP_centre = LBP (localBinaryPatternImage);
% Let's compute and display the concatenation of all histogram.
[counts, binLocs] = imhist(uint8(LBP_centre), 256);
allCounts = [allCounts, counts];
allBinLocs = [allBinLocs, binLocs + length(allBinLocs)]
% "+ length(allBinLocs)" is to shift range from 256-511, and so on for each block.
end
end
end
figure;
stem(allBinLocs, allCounts);
答案 0 :(得分:0)
使用return values of imhist
存储bin位置和值,而不是直接在循环中绘制它们。
然后,您可以将它们连接在一个大数组中并显示直方图。
allCounts = []
allBinLocs = []
for noOfGRAYimage = 1:length(total_gray_images)
% ...
for i=1:overlapp:(r-B)+1;
% ...
for j=1:overlapp:(c-B)+1;
% ...
[counts, binLocs] = imhist(uint8(LBP_centre), 256);
allCounts = [allCounts; counts(:)];
allBinLocs = [allBinLocs; binLocs(:) + length(allBinLocs)];
% "+ length(allBinLocs)" is to shift range from 256-511, and so on for each block.
end
end
end
figure;
stem(allBinLocs, allCounts);