Question

在我的情况下我有一个表单，当我点击添加按钮功能和图像字段行将动态添加，我可以添加数据。现在我想删除某个位置的特定行。我尝试使用拼接切片和弹出。但pop只删除最后一行。当我使用切片和拼接时，删除的行的数据没有清除，行本身也没有清除。这是我的代码，这是

$scope.rows = [];  
$scope.current_rows = 1;
$scope.destination_details = {};
$scope.rows.push({
    row_num: $scope.current_rows
});

// code for adding a row dynamically
 $scope.add = function () {
    $scope.rows.push({
        row_num: $scope.current_rows + 1,
    });
};

//code for removing row dynamically
     $scope.remove = function ($index) {
    $scope.rows.splice({
        row_num: ($index, 1),
    });
    $scope.destination_details.destination_features1[$index] = '';
    $scope.destination_image_arr[$index] = '';
};

当我使用时：

    $scope.rows.slice({
        row_num: ($index, 1),
    });

正在清除该特定位置的数据，但该行未关闭。当我使用时：

   $scope.rows.pop({
        row_num: $scope.current_rows - 1,
    });

仅删除最后一行。这是我的HTML代码：

  <div class="row" ng-repeat="row in rows track by $index">             
            <div class="col s12 m4">
                <label>Upload Images </label>
                <div class="input-field col s11">
                    <input  type="file" id="image" name="image_{{$index}}" ng-files="get_files($files,$index)" ng-model="destination_details.image[$index]" ng-required="true" multiple/>
                    <div ng-messages="add_destination_form['image_' + $index].$error" ng-if="add_destination_form['image_' + $index].$dirty || add_destination_form.$submitted">
                        <div ng-message-exp="['required']">
                            <span class="error">Please add alteast one image !</span> 
                        </div>
                    </div>
                    <div ng-if="destination_image_arr[$index].length > 0" id="post_img">                      
                        <a ng-click="uncheck_files($index)"  title="close" style="cursor:pointer" class="close_image_upload">X</a>    
                        <img  class="thumb" ng-src="{{destination_image_arr[$index]}}">
                    </div>
                    <div id="img_err_msg"></div>
                    <br><br><br>
                  </div>                                       
               </div>
            <div class="col s12 m4" >
                <label for="destination_features1" >Features</label>
                <textarea  id="destination_features1" name="destination_features1_{{$index}}" ng-model="destination_details.destination_features1[$index]" placeholder="Mandatory" type="text" ng-required="true"></textarea>                        
                <div ng-messages="add_destination_form['destination_features1_' + $index].$error" ng-if="add_destination_form['destination_features1_' + $index].$dirty || add_destination_form.$submitted">
                    <div ng-message-exp="['required']">
                        <span class="error">Description is required</span>  
                    </div>
                </div> 
            </div>
             <div class="col s12 m4">   
                <button ng-show="show_removebtn" id="removeButton" class="waves-effect waves-light btn" ng-click="removeDynamically($index)" type="button">Remove</button>                              
            </div>
        </div>
        <div class="col s12 m4">                 
         <button class="waves-effect waves-light btn" ng-click="addDynamically()" type="button">Add More</button>                               
        </div>

任何帮助都将不胜感激。谢谢

Answer 1

如果你想拼接一个特定的位置。这是参考Array.prototype.splice()

＆＃13;

var array = [1, 2, 3, 4]
array.splice(2, 1);
console.log(array);

＆＃13;

此处位置2已被删除，它将删除第二个参数中的1次定义。

在您的代码中尝试执行此操作：

$scope.rows.splice($index, 1);

Answer 2

试试这个

＆＃13;

    var array = [1, 2, 3, 4]
    console.log('array befor removing elemnt '+array);
    var postion = 1;
    var numberOFElemntsToRemove = 1;
    array.splice(postion, numberOFElemntsToRemove );
    console.log('array after removing elemnt '+array);

＆＃13;

在你的代码中而不是这个

$scope.rows.splice({
    row_num: ($index, 1),
});

使用

$scope.rows.splice($index, 1);

如何从angularjs / javascript中的特定位置删除数组中的元素

2 个答案: