Question

我正在寻找一种使用Swift 3.0将此字符串转换为数组的方法

let arrayString: String = "[\"One\", \"Two\", \"Three\", \"Four\"]"

// Should be converted into:

let array: [String] = [
    "One",
    "Two",
    "Three",
    "Four"
]

如果我使用,作为分隔符将其分隔为令牌，则会包含[和]，因此无法正常工作。如何正确转换？

注意：

问题不同于： Simple and clean way to convert JSON string to Object in Swift

我没有尝试转换其中包含多个键的JSON对象。

Answer 1

它是一个JSON字符串，你必须使用JSONSerialization在普通字符串数组中转换它。

Swift 3.0

func convertToArray(str: String) -> [String]? {

    let data = str.data(using: .utf8)

    do {
        return try JSONSerialization.jsonObject(with: data!, options: []) as? [String]
    } catch {
        print(error.localizedDescription)
    }

   return nil

 }

let aString: String = "[\"One\", \"Two\", \"Three\", \"Four\"]"

let arrayString = convertToArray(str: aString)

print(arrayString) // ["One", "Two", "Three", "Four"]

Answer 2

可以通过多种方式实现您的目标，但我认为最简单的方法之一是：

let newArray = arrayString
 .replacingOccurrences(of: "[", with: "")
 .replacingOccurrences(of: "]", with: "")
 .replacingOccurrences(of: "\"", with: "")
 .components(separatedBy: ",")

输出应为：

["One", " Two", " Three", " Four"]

修改正如@MartinR建议的那样，如果任何字符串包含逗号或方括号，则上一个答案不起作用。所以要解决这个问题，你可以删除方括号，假设在开头和结尾总是有，然后使用正则表达式匹配\"()\"内的所有内容，如下面的代码所示：

让我们使用以下函数来匹配正则表达式：

func matches(for regex: String, in text: String) -> [String] { do { let regex = try NSRegularExpression(pattern: regex) let nsString = text as NSString let results = regex.matches(in: text, range: NSRange(location: 0, length: nsString.length)) return results.map { nsString.substring(with: $0.range)} } catch let error { print("invalid regex: \(error.localizedDescription)") return [] } }

有关详情，请参阅@MartinR回答here

使用该功能，我们可以使用以下代码来实现我们想要的目标：

let str = "[\"One[\",\"T,w,o,\",\"Thr,ee,,,\",\"Fo,ur,,,\"]" // remove the square brackets from the array let start = str.index(str.startIndex, offsetBy: 1) let end = str.index(str.endIndex, offsetBy: -1) let range = start..<end let newString = str.substring(with: range) // match the regex let matched = matches(for: "(?<=\")(.*?)(?=\")", in: newString) // ["One[", ",", "T,w,o,", ",", "Thr,ee,,,", ",", "Fo,ur,,,"]

但是之前的matched包含了数组中的","，所以让我们使用以下代码修复它：

let stringArray = matched.enumerated() .filter { $0.offset % 2 == 0 } .map { $0.element }

使用以下输出：

["One[", "T,w,o,", "Thr,ee,,,", "Fo,ur,,,"]

我希望这会对你有所帮助。

Answer 3

以下是转换为数组的自定义代码：

var arrayString: String = "[\"One\", \"Two\", \"Three\", \"Four\"]"
arrayString = arrayString.replacingOccurrences(of: "[", with: "")
arrayString = arrayString.replacingOccurrences(of: "]", with: "")
arrayString = arrayString.replacingOccurrences(of: " ", with: "")
arrayString = arrayString.replacingOccurrences(of: "\"", with: "")
print("\(arrayString)")
var arr: [Any] = arrayString.components(separatedBy: ",")
print("\(arr)")

如果从API及其JSON获得上述字符串，则使用以下内容：

extension String {
    func toJSON(): Any? {
        guard let data = self.data(using: .utf8, allowLossyConversion: false) else { return nil }
        return try? JSONSerialization.jsonObject(with: data, options: .mutableContainers)
    }
}

解析包含＆＃34;字符串数组＆＃34;使用Swift 3.0进入Array

3 个答案: