return语句不返回任何内容

时间:2017-08-16 20:27:51

标签: php rest api mysqli

基本上,我有一个函数getPayments()。此函数应执行查询,从多个表中选择(已连接)。这是我的代码

function getPayments($userid, $schoolyear) {
    $stmt = $this->con->prepare("SELECT tbl_payment.payment_receipt_type AS RType, tbl_payment.payment_receipt_number AS RNumber, tbl_feetype.feetype_name AS FName, tbl_payment.payment_amount AS PAmount, tbl_month.month_date AS MDate, tbl_payment.payment_dateadded AS PAdded 
FROM tbl_payment
  INNER JOIN tbl_student ON tbl_student.student_id = tbl_payment.student_id 
  INNER JOIN tbl_schoolyear ON tbl_schoolyear.schoolyear_id = tbl_payment.schoolyear_id
  INNER JOIN tbl_feetype ON tbl_feetype.feetype_id = tbl_payment.feetype_id 
  INNER JOIN tbl_month ON tbl_month.month_id = tbl_payment.month_id   
  WHERE tbl_payment.schoolyear_id = ? AND tbl_payment.student_id = ? ORDER BY payment_dateadded DESC");

    $stmt->bind_param("ss", $userid, $schoolyear);
    $stmt->execute();
    $stmt->bind_result($RType, $RNumber, $FName, $PAmount, $MDate, $PAdded);

    $payments = array();

    while ($stmt->fetch()) {
        $temp = array();

        $temp['paymenttype'] = $RType;
        $temp['receiptnumber'] = $RNumber;
        $temp['feename'] = $FName;
        $temp['paymentamount'] = $PAmount;
        $temp['monthname'] = $MDate;
        $temp['paymentdate'] = $PAdded;

        array_push($payments, $temp);
    }

    return $payments;
}

在我的index.php文件中:

//getting payment details for a user
$app->get('/payment/{id}/{sy}', function (Request $request, Response $response) {
$route = $request->getAttribute('route');
// $userid = $request->getAttribute('id');
$userid = $route->getArgument('id');
$schoolyear = $route->getArgument('sy');
    // $schoolyear = $request->getAttribute('sy');
    $db = new DbOperation();
    $payments = $db->getPayments($userid, $schoolyear);
    $response->getBody()->write(json_encode(array("payments" => $payments)));
});

^这行代码将从getPayment()函数获取返回的数组结果,然后将其编码为json。

问题是,在Postman中测试我的API之后,Postman只给了我这个结果

{"payments":[]} 

请帮帮我。谢谢。 (抱歉我的英语不好)

1 个答案:

答案 0 :(得分:-1)

找到答案。 我错放了一些变量。

$stmt->bind_param("ss", $userid, $schoolyear);应写为$stmt->bind_param("ss", $schoolyear, $userid);

现在一切正常。谢谢。 :)

此主题现已关闭。

相关问题