JSONObject baseJsonResponse = new JSONObject(newsJSON);
JSONObject responseObj = baseJsonResponse.getJSONObject("response");
JSONArray resultArray = responseObj.getJSONArray("results");
for (int i =0;i<resultArray.length();i++){
String sectionName = resultArray.getString("sectionName");}
我想获取此网址的部分名称: https://content.guardianapis.com/search?api-key=e11b8d10-d6ef-4fb7-9c12-094c58d37687
答案 0 :(得分:0)
你可以像这样获得Json Value。
JSONObject baseJsonResponse = new JSONObject(newsJSON);
JSONObject responseObj = null;
try {
responseObj = baseJsonResponse.getJSONObject("response");
JSONArray resultArray = responseObj.getJSONArray("results");
int size = resultArray.length();
for (int i =0;i<size;i++){
JSONObject myJson = resultArray.getJSONObject(i);
String sectionName = myJson.getString("sectionName");
}
} catch (JSONException e) {
e.printStackTrace();
}