Question

如何编写单个查询，通过product_id给出SUM（Entrance.quantity） - SUM（Buying.quantity）组。

问题出在第一个或第二个表中不存在的行中。可以这样做吗？

入口：

+---+--------------+---------+
| id | product_id | quantity|
+---+--------------+---------+
| 1 | 234 | 15 |
| 2 | 234 | 35 |
| 3 | 237 | 12 |
| 4 | 237 | 18 |
| 5 | 101 | 10 |
| 6 | 150 | 12 |
+---+--------------+---------+

购买：

+---+------------+-------------+
| id | product_id | quantity|
+---+------------+-------------+
| 1 | 234 | 10 |
| 2 | 234 | 20 |
| 3 | 237 | 10 |
| 4 | 237 | 10 |
| 5 | 120 | 15 |
+---+------------+------------+

期望的结果：

+--------------+-----------------------+
| product_id | quantity_balance |
+--------------+-----------------------+
| 234 | 20 |
| 237 | 10 |
| 101 | 10 |
| 150 | 12 |
| 120 | -15 |
+--------------+-----------------------+

Answer 1

这很棘手，因为产品可能在一个表中但不在另一个表中。一种方法使用union all和group by：

select product_id, sum(quantity)
from ((select e.product_id, quantity
       from entrance e
      ) union all
      (select b.product_id, - b.quantity
       from buying b
      )
     ) eb
group by product_id;

Answer 2

SELECT  product_id ,
        ( Tmp1.enterquantity - Tmp2.buyquantity ) AS Quantity_balance
FROM    entrance e1
        CROSS APPLY ( SELECT    SUM(quantity) AS enterquantity
                      FROM      Entrance e2
                      WHERE     e1.product_id = e2.product_id
                    ) Tmp1
        CROSS APPLY ( SELECT    SUM(quantity) AS buyquantity
                      FROM      Buying b2
                      WHERE     e1.product_id = b2.product_id
                    ) Tmp2
GROUP BY Product_id,( Tmp1.enterquantity - Tmp2.buyquantity )

用不同的行数减去两列不同的表

2 个答案: