保持上一年数据的累积总和 - SQL Server

时间:2017-08-21 15:47:13

标签: sql-server

我正在尝试编写一个查询包含id,date和value的数据点的查询。这些数据点代表员工的休假时间。

以下是一些示例数据点(请假时间)的示例:

+------------+-------+-------+-------------+
|    Date    | Value | Total |   Status    |
+------------+-------+-------+-------------+
| 8/20/2015  |  0.25 |  0.25 |             |
| 1/11/2016  |     1 |  1.25 |             |
| 5/27/2016  |   0.5 |  1.75 |             |
| 8/5/2016   |  0.25 |     2 |             |
| 9/13/2016  |     0 |  1.75 |             |
| 9/28/2016  |  0.25 |     2 |             |
| 9/29/2016  |  0.25 |  2.25 |             |
| 10/17/2016 |     0 |  2.25 |             |
| 10/17/2016 |     1 |  3.25 | Verbal      |
| 11/17/2016 |  0.25 |   3.5 |             |
| 12/1/2016  |     1 |   4.5 | Written     |
| 12/2/2016  |     1 |   5.5 | Final       |
| 12/6/2016  |  0.25 |  5.75 |             |
| 12/14/2016 |  0.25 |     6 | Termination |
| 12/19/2016 |  0.25 |  6.25 |             |
| 1/6/2017   |  0.25 |   6.5 |             |
| 2/15/2017  |  0.25 |  5.75 | Final       |
| 3/15/2017  |  0.25 |     6 | Termination |
| 4/17/2017  |  0.25 |  6.25 |             |
| 5/8/2017   |     0 |  6.25 |             |
| 5/9/2017   |     1 |  7.25 |             |
| 5/21/2017  |  0.25 |   7.5 |             |
|            |       |       |             |
+------------+-------+-------+-------------+

我想要一个计算上述结果的查询。总列由当前数据点日期的1年内先前数据点的总和计算。因此,如果当前数据点的日期为2016年9月29日,我想将所有之前的数据点加在2015年9月29日至2016年9月29日之间。

此查询的最终目标是根据他们的休假时间(数据点)查看一个人在去年内是否有两个最终警告。根据我提供的示例,我们在2016年12月12日和2017年2月15日发布了最终警告,这些警告发生在去年(2016年8月21日 - 2017年8月21日)。

这样做的最佳方式是什么?

以下是我目前的情况:

SELECT 
    a.dtmDATEAPP AS [Date],
    MAX(CASE WHEN a.dtmDATEAPP = b.dtmDATEAPP THEN a.strOCCUR END) AS [Value],
    SUM(b.strOCCUR) AS Total,
    CASE 
       WHEN SUM(b.strOCCUR) >= 5 AND SUM(b.strOCCUR) < 6 
          THEN 'Final' 
    END AS [Status]
FROM 
    [Attendance].[dbo].[TIMEUSE] a
JOIN 
    [Attendance].[dbo].[TIMEUSE] b ON b.dtmDATEAPP BETWEEN DATEADD(year, -1, a.dtmDATEAPP) AND a.dtmDATEAPP
WHERE 
    a.lngEMPID = 1162002 
    AND a.Absence <> 'Scheduled' 
    AND b.lngEMPID = 1162002 
    AND b.Absence <> 'Scheduled'
GROUP BY 
    a.dtmDATEAPP
ORDER BY 
    a.dtmDATEAPP

我不确定在过去一年中员工是否有2个最终警告的最佳途径。

非常感谢所有帮助。

1 个答案:

答案 0 :(得分:0)

这样的事可能会对你有所帮助:

declare @TimeUsage table
(
missingDate date,
absence varchar(20),
pctDay decimal(6,2),
status varchar(20),
employeeid int
)
INSERT INTO @TimeUsage VALUES
('8/20/2015', 'Unscheduled', 0.25, '', 1162002),              
('1/11/2016', 'Unscheduled', 1, '', 1162002),              
('5/27/2016', 'Unscheduled', 0.5, '', 1162002),              
('8/5/2016', 'Unscheduled', 0.25, '', 1162002),              
('9/13/2016', 'Unscheduled', 0, '', 1162002),              
('9/28/2016', 'Unscheduled', 0.25, '', 1162002),              
('9/29/2016', 'Unscheduled', 0.25, '', 1162002),              
('10/17/2016', 'Unscheduled', 0, '', 1162002),              
('10/17/2016', 'Unscheduled', 1, 'Verbal', 1162002),        
('11/17/2016', 'Unscheduled', 0.25, '', 1162002),              
('12/1/2016', 'Unscheduled', 1, 'Written', 1162002),       
('12/2/2016', 'Unscheduled', 1, 'Final', 1162002),         
('12/6/2016', 'Unscheduled', 0.25, '', 1162002),              
('12/14/2016', 'Unscheduled', 0.25, 'Termination', 1162002),   
('12/19/2016', 'Unscheduled', 0.25, '', 1162002),              
('1/6/2017', 'Unscheduled', 0.25, '', 1162002),              
('2/15/2017', 'Unscheduled', 0.25, 'Final', 1162002),         
('3/15/2017', 'Unscheduled', 0.25, 'Termination', 1162002),   
('4/17/2017', 'Unscheduled', 0.25, '', 1162002),              
('5/8/2017', 'Unscheduled', 0, '', 1162002),              
('5/9/2017', 'Unscheduled', 1, '', 1162002),              
('5/21/2017', 'Unscheduled', 0.25, '', 1162002)  

;WITH cte AS
(SELECT missingDate, pctDay, 
(SELECT SUM(pctDay) FROM @TimeUsage 
WHERE missingDate <= d.missingDate 
AND missingDate >= DATEADD(yy,-1,d.missingDate) 
AND employeeid = d.employeeid
AND absence <> 'Scheduled') as prevYrTot, 
(SELECT COUNT(*) FROM @TimeUsage 
WHERE missingDate <= d.missingDate 
AND missingDate >= DATEADD(yy,-1,d.missingDate) 
AND employeeid = d.employeeid
AND status = 'Final') AS FinalCount,
status,employeeid 
from @TimeUsage d)
SELECT * FROM cte where employeeid IN 
(SELECT DISTINCT(employeeid) FROM cte WHERE FinalCount > 1)

修改

如果最终状态由prevyrtot决定,那么试试这个:

declare @TimeUsage table
(
missingDate date,
absence varchar(20),
pctDay decimal(6,2),
employeeid int
)
INSERT INTO @TimeUsage VALUES
('8/20/2015', 'Unscheduled', 0.25, 1162002),              
('1/11/2016', 'Unscheduled', 1, 1162002),              
('5/27/2016', 'Unscheduled', 0.5, 1162002),              
('8/5/2016', 'Unscheduled', 0.25, 1162002),              
('9/13/2016', 'Unscheduled', 0, 1162002),              
('9/28/2016', 'Unscheduled', 0.25, 1162002),              
('9/29/2016', 'Unscheduled', 0.25, 1162002),              
('10/17/2016', 'Unscheduled', 0, 1162002),              
('10/17/2016', 'Unscheduled', 1, 1162002),        
('11/17/2016', 'Unscheduled', 0.25, 1162002),              
('12/1/2016', 'Unscheduled', 1, 1162002),       
('12/2/2016', 'Unscheduled', 1, 1162002),         
('12/6/2016', 'Unscheduled', 0.25, 1162002),              
('12/14/2016', 'Unscheduled', 0.25, 1162002),   
('12/19/2016', 'Unscheduled', 0.25, 1162002),              
('1/6/2017', 'Unscheduled', 0.25, 1162002),              
('2/15/2017', 'Unscheduled', 0.25, 1162002),         
('3/15/2017', 'Unscheduled', 0.25, 1162002),   
('4/17/2017', 'Unscheduled', 0.25, 1162002),              
('5/8/2017', 'Unscheduled', 0, 1162002),              
('5/9/2017', 'Unscheduled', 1, 1162002),              
('5/21/2017', 'Unscheduled', 0.25, 1162002)  

;WITH cte as
(SELECT missingDate, pctDay, prevYrTot, employeeid, 
CASE WHEN prevYrTot >= 5 AND prevYrTot < 6 
THEN 'Final' ELSE '' END AS Status FROM
(SELECT missingDate, pctDay, 
(SELECT SUM(pctDay) FROM @TimeUsage 
WHERE missingDate <= d.missingDate 
AND missingDate >= DATEADD(yy,-1,d.missingDate) 
AND employeeid = d.employeeid
AND absence <> 'Scheduled') as prevYrTot, 
employeeid 
from @TimeUsage d) tu)
SELECT missingDate, pctDay, prevYrTot, employeeid, Status FROM cte 
WHERE employeeid IN 
(SELECT DISTINCT employeeid FROM (SELECT employeeid, COUNT(*) as FinalCount FROM cte 
WHERE Status = 'Final'
GROUP BY employeeid
HAVING Count(*) > 1) de)

我认为这样做你想要的,但你需要测试!它适用于给定的数据。

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