Question

我想从服务器发送和接收数据。为此，我使用了Volley。代码如下。 Volley可以Json格式接收数据。服务器可以Json格式发送和接收数据。如何将此Json数据转换为用户可读的JAVA格式？其他课程大约有10种方法。以下类包含网络调用的方法，还与MainActivity进行交互。

public class Api_Volley {
    String data;
    String flag;
    public void my_volley_post (String url , JSONObject jsonObject , final Context context ) {
        JsonObjectRequest jsonObjectRequest = new JsonObjectRequest(Request.Method.POST, url  , jsonObject , new Response.Listener(){
            @Override
            public void onResponse(Object response) {

                String flag = response.toString();
                Toast.makeText( context , flag , Toast.LENGTH_LONG ).show();
            }
        },new Response.ErrorListener(){
            @Override
            public void onErrorResponse(VolleyError error) {
                Toast.makeText(context , "Wrong" , Toast.LENGTH_LONG).show();
                error.printStackTrace();
            }
        });
        ApiVolleySingeltonClass.getInstance(context).addToRequestque(jsonObjectRequest);
    }
}

另一堂课的方法：

  public void showAllOrderByUserId() {
        try {
            data_args.put("userId", 2);
        } catch (JSONException e) {
            e.printStackTrace();
        }
        try {
            data_action.put("action", "showAllOrderByUserId");
            data_action.put("args", data_args);
        } catch (JSONException e) {
            // TODO Auto-generated catch block
            e.printStackTrace();
        }
        route = "/order";
        new Api_Volley().my_volley_post(addUserUrl + route, data_action, context);
    }

Answer 1

您可以使用
等json数据
{“userNodes”：[{“id”：“1”，“name”：“Enamul Haque”}}}

你可以像凌晨一样使用凌空

 private void doLoginAction() {


    String url_login = "http://www.lineitopkal.com/android/login.php";


 StringRequest stringRequest = new StringRequest(Request.Method.POST, url_login,
 new Response.Listener<String>() {
    @Override
    public void onResponse(String response) {
        //pDialog.dismiss();


        try {
            JSONObject jsonObject = new JSONObject(response);
            JSONArray loginNodes = jsonObject.getJSONArray("userNodes");
            for (int i = 0; i < loginNodes.length(); i++) {
                JSONObject jo = loginNodes.getJSONObject(i);
                String id = jo.getString("id");
                Log.e("id ::",id);                                
                String name = jo.getString("name");
                Log.e("name ::",name);


            }
        } catch (JSONException e) {
            e.printStackTrace();
          }


      }
   },
  new Response.ErrorListener() {
    @Override
    public void onErrorResponse(VolleyError error) {

        try {

            if (error instanceof TimeoutError ) {
                //Time out error

            }else if(error instanceof NoConnectionError){
                //net work error

            } else if (error instanceof AuthFailureError) {
                //error

            } else if (error instanceof ServerError) {
                //Erroor
            } else if (error instanceof NetworkError) {
                //Error

            } else if (error instanceof ParseError) {
                //Error

            }else{
                //Error
            }
            //End


        } catch (Exception e) {


        }

       }
   }) {
 @Override
 protected Map<String, String> getParams() {
   Map<String, String> params = new HashMap<>();
    //Post parameter like bellow
    params.put("uname", "era@gmail.com");
    params.put("pass", "123456");



     return params;
     }

  };

    RequestQueue requestQueue = Volley.newRequestQueue(this);
    requestQueue.add(stringRequest);
     }

Answer 2

像这样创建您的响应格式

public class Post {
    long id;
    Date dateCreated;
    String title;
    String author;
    String url;
    String body;
    }

在提出以下请求后

public void my_volley_post (String url , JSONObject jsonObject , final Context context ) {
        JsonObjectRequest jsonObjectRequest = new JsonObjectRequest(Request.Method.POST, url  , jsonObject , new Response.Listener(){
            @Override
            public void onResponse(String response) {
         GsonBuilder gsonBuilder = new GsonBuilder();
         gson = gsonBuilder.create();

//这将是您的实体

      Post post = gson.fromJson(response, Post.class));


        },new Response.ErrorListener(){
            @Override
            public void onErrorResponse(VolleyError error) {
                Toast.makeText(context , "Wrong" , Toast.LENGTH_LONG).show();
                error.printStackTrace();
            }
        });
        ApiVolleySingeltonClass.getInstance(context).addToRequestque(jsonObjectRequest);
    }

Answer 3

你必须解析JSON并且必须根据需要显示：

通过这个你可以使用GSON（很容易）使用此站点将JSON转换为pojo类。 Click here

这些是您可以使用和实施的参考网站：

http://www.vogella.com/tutorials/JavaLibrary-Gson/article.html

https://www.javacodegeeks.com/2011/01/android-json-parsing-gson-tutorial.html

https://kylewbanks.com/blog/tutorial-parsing-json-on-android-using-gson-and-volley

服务器响应是json形式

3 个答案: