将URL转换为超链接

时间:2017-08-22 10:00:26

标签: ios objective-c hyperlink

我正在开发一个应用程序,我在其中使用一些网址分享事件图像 共享事件图像时,我正在使用此内容:=

“嘿!我刚刚看到”Venue Name“通过XXXX App获得了”活动名称“!我们 应该看看。 https://app.com/site/redirectlink?event_id=%@

现在我可以将此“https://app.com/site/redirectlink?event_id=%@”链接到“此处”超链接吗?

我通过“UIActivityViewController”分享这些内容。 实际上,此URL(https://app.com/site/redirectlink?event_id=%@)稍后用于深层链接,当用户单击此链接时,它将根据event_id重定向到特定事件。 而不是我想在这里使用的整个URL(作为超链接)。

2 个答案:

答案 0 :(得分:1)

可能会帮助你这样做..

NSString *url=@"https://app.com/site/redirectlink?event_id=%@";
    NSString * title =[NSString stringWithFormat:@"Hey! I just saw \"Venue Name\" is having \"Event Name\" through the XXXX App! We should check it out <html> <body> <a href = '%@'>here</a> </body> </html>",url];
    NSArray* dataToShare = @[title];
    UIActivityViewController* activityViewController =[[UIActivityViewController alloc] initWithActivityItems:dataToShare applicationActivities:nil];
    activityViewController.excludedActivityTypes = @[UIActivityTypeAirDrop];
    [self presentViewController:activityViewController animated:YES completion:^{}];

答案 1 :(得分:0)

您可能需要深层链接网址:projectName://myapp?event_id=12345

添加 info.plist

<key>CFBundleURLTypes</key>
    <array>
        <dict>
            <key>CFBundleURLName</key>
            <string>com.erimkurt.projectName</string>
            <key>CFBundleURLSchemes</key>
            <array>
                <string>projectName</string>
            </array>
        </dict>
    </array>

添加 appdelegete.m

- (BOOL)application:(UIApplication *)application openURL:(NSURL *)url
  sourceApplication:(NSString *)sourceApplication annotation:(id)annotation {

        NSLog(@"Calling Application Bundle ID: %@", sourceApplication);
        NSLog(@"URL scheme:%@", [url scheme]);
        NSLog(@"URL query: %@", [url query]);

        return YES;
}

- (BOOL)application:(UIApplication *)application handleOpenURL:(NSURL *)url
{
    if (!url) {  return NO; }

    UIAlertView *alertView;
    alertView = [[UIAlertView alloc] initWithTitle:@"Launch by URL" message:@"This app was launched from a URL" delegate:nil cancelButtonTitle:@"OK" otherButtonTitles:nil];
    [alertView show];

    NSString *urlString = [url absoluteString];
    [[NSUserDefaults standardUserDefaults] setObject:urlString forKey:@"url"];
    [[NSUserDefaults standardUserDefaults] synchronize];

    return YES;
}

添加 viewController.m

NSString *url = [[NSUserDefaults standardUserDefaults] objectForKey:@"url"];
    NSLog(@"MYAPPURL: %@",url);
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