Question

我有一个包含多个日期时间戳的文本字段，我只需要删除时间戳。此字段中还有带回车符的文本。我想维护文本，日期和回车。

任何人都有这方面的经验，可以分享选择来完成这个吗？

以下是文本字段的示例：

[10/19/2015 5:24:02 PM Tech1] Repaired heaters [10/21/2015 8:36:28 AM Tech1] CHECKED ALL HEATER OPERATION

非常感谢任何见解。在此先感谢您的帮助！

Answer 1

这是STUFF和分词功能的一种方式，考虑单位和双位小时。

declare @table table (vars varchar(4000))
insert into @table
values
('[10/19/2015 5:24:02 PM Tech1] Repaired heaters' + char(10) + '[10/21/2015 12:36:28 AM Tech1] CHECKED ALL HEATER OPERATION' + char(13) + '[10/22/2015 3:36:28 PM Tech1] somethingelse')
,('[11/19/2015 5:24:02 PM Tech1] asdfsdaf  [11/21/2015 8:36:28 AM Tech1] dddddddddddd [11/22/2015 3:36:28 PM Tech1] yyyyyyyyy')
,('[1/19/2015 11:24:02 PM Tech1] here went something  [09/21/2015 08:36:28 AM Tech1] Tech 1 did something else[11/22/2015 10:36:28 PM Tech1] last')

;with cte as(
select
    vars
    ,RN = dense_rank() over (order by vars)
    --,Item
    ,Item = '[' + stuff(Item,charindex(' ',Item), 3 + case when charindex(' AM ',Item) = 0 then charindex(' PM ',Item) else charindex(' AM ',Item) end  - charindex(' ',Item),'')
from
    @table
    cross apply
    dbo.DelimitedSplit8K(vars,'[')
where
    Item <>'')



select distinct
    vars
    ,RemovedTime =
                STUFF((
                      SELECT ' ' + c2.Item
                      FROM cte c2
                      WHERE c.RN = c2.RN
                      FOR XML PATH(''), TYPE).value('.', 'NVARCHAR(MAX)'), 1, 1, '')
from
    cte c

分割器可以在Jeff Moden's Article

中找到

CREATE FUNCTION [dbo].[DelimitedSplit8K] (@pString VARCHAR(8000), @pDelimiter CHAR(1))
--WARNING!!! DO NOT USE MAX DATA-TYPES HERE!  IT WILL KILL PERFORMANCE!

RETURNS TABLE WITH SCHEMABINDING AS
RETURN

/* "Inline" CTE Driven "Tally Table" produces values from 1 up to 10,000...
enough to cover VARCHAR(8000)*/

  WITH E1(N) AS (
                 SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1 UNION ALL
                 SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1 UNION ALL
                 SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1
                ),                          --10E+1 or 10 rows
       E2(N) AS (SELECT 1 FROM E1 a, E1 b), --10E+2 or 100 rows
       E4(N) AS (SELECT 1 FROM E2 a, E2 b), --10E+4 or 10,000 rows max
 cteTally(N) AS (--==== This provides the "base" CTE and limits the number of rows right up front
                     -- for both a performance gain and prevention of accidental "overruns"
                 SELECT TOP (ISNULL(DATALENGTH(@pString),0)) ROW_NUMBER() OVER (ORDER BY (SELECT NULL)) FROM E4
                ),
cteStart(N1) AS (--==== This returns N+1 (starting position of each "element" just once for each delimiter)
                 SELECT 1 UNION ALL
                 SELECT t.N+1 FROM cteTally t WHERE SUBSTRING(@pString,t.N,1) = @pDelimiter
                ),
cteLen(N1,L1) AS(--==== Return start and length (for use in substring)
                 SELECT s.N1,
                        ISNULL(NULLIF(CHARINDEX(@pDelimiter,@pString,s.N1),0)-s.N1,8000)
                   FROM cteStart s
                )
--===== Do the actual split. The ISNULL/NULLIF combo handles the length for the final element when no delimiter is found.
 SELECT ItemNumber = ROW_NUMBER() OVER(ORDER BY l.N1),
        Item       = SUBSTRING(@pString, l.N1, l.L1)
   FROM cteLen l
;
GO

Answer 2

更新：误解了要求，根据以下评论更新了我的解决方案。

为此，您需要PatternSplitCM。

declare @table table (someid int identity, somestring varchar(1000));
insert @table(somestring) values 
('[10/19/2015 5:24:02 PM Tech1] Repaired heaters [10/21/2015 8:36:28 AM Tech1] CHECKED ALL HEATER OPERATION'),
('[02/28/2015 5:24:02 PM Tech1] Repaired more stuff [12/01/2015 2:36:28 AM Tech1] CHECKED ALL HEATER OPERATION');

with parseMe as
(
  select 
    someid, 
    ItemNumber,
    Item = case 
           when Item like '[0-9]:[0-9][0-9]:[0-9][0-9]' then '<exclude>' 
           else replace(replace(item, ' AM ',''), ' PM ', '') end
  from @table t
  cross apply dbo.PatternSplitCM(t.somestring, '[0-9:/]')
)
select
  someid,
  newString = 
    replace((
      select item+''
      from parseMe p2 
        where p1.someid = p2.someid 
      order by ItemNumber
      for xml path(''), type
    ).value('.', 'varchar(1000)'), '<exclude>','')
from parseMe p1
group by someid;

SQL从字符串的任何部分删除多个时间戳

2 个答案: