Question

我有3个表，我正在尝试在order_products和order_products_status_names之间建立关系。我有名为order_product_statuses的transition / pivot表。问题是我的PK，因为我在表格订单3 Pk，我不知道如何通过关系连接这3个表。我的迁移是：

表订购产品：

 public function up()
{
    Schema::create('order_products', function (Blueprint $table) {
        $table->integer('order_id')->unsigned();
        $table->integer('product_id')->unsigned();
        $table->integer('ordinal')->unsigned();
        $table->integer('size');

        $table->primary(['order_id', 'product_id', 'ordinal']);
        $table->foreign('order_id')->references('id')->on('orders');
        $table->foreign('product_id')->references('id')->on('products');
    });
}

表格订单产品状态 - 这是我在order_products和order_product_status_names之间的转换/数据透视表

 public function up()
{
    Schema::create('order_product_statuses', function (Blueprint $table) {
        $table->integer('order_id')->unsigned();
        $table->integer('product_id')->unsigned();
        $table->integer('status_id')->unsigned();
        $table->integer('ordinal')->unsigned();
        $table->dateTime('created_at')->default(DB::raw('CURRENT_TIMESTAMP'));

        $table->foreign('order_id')->references('id')->on('orders');
        $table->foreign('status_id')->references('id')->on('order_product_status_names');
        $table->primary(['order_id', 'product_id', 'ordinal']);
    });
}

最后一个是订购产品状态名称

public function up()
{
    Schema::create('order_product_status_names', function (Blueprint $table) {
        $table->integer('id')->unsigned();
        $table->string('name');
        $table->string('code');
        $table->dateTime('created_at')->default(DB::raw('CURRENT_TIMESTAMP'));

        $table->primary('id');
    });
}

我知道这是关系blengsToMany有两种方式，但我不知道或者我可以声明这种关系（从order_products到order_product_status_names和反向）？

Answer 1

好的避风港花了很多时间在这上面，但这就是我要做的事情。同样正如@Devon所提到的，我可能会为每个表添加id，因为Eloquent并不是真正为复合键设计的。正如我的一条评论中提到的，我通常会创建启动和更新脚本，因此语法可能不完全正确：

public function up() {
    Schema::create('order_products', function (Blueprint $table) {
        $table->bigIncrements('id')->unsigned();
        $table->integer('order_id')->unsigned();
        $table->integer('product_id')->unsigned();
        $table->integer('order_product_statuses_id')->unsigned();
        $table->integer('ordinal')->unsigned();
        $table->integer('size');

        $table->primary('id');
        $table->foreign('order_id')->references('id')->on('orders');
        $table->foreign('product_id')->references('id')->on('products');
        $table->foreign('order_product_statuses_id')->references('id')->on('order_product_statuses');
    });
}

public function up() {
    Schema::create('order_product_statuses', function (Blueprint $table) {
        $table->bigIncrements('id')->unsigned();
        $table->integer('product_id')->unsigned();
        $table->integer('status_id')->unsigned();
        $table->integer('ordinal')->unsigned();
        $table->dateTime('created_at')->default(DB::raw('CURRENT_TIMESTAMP'));

        $table->primary('id');
        $table->foreign('status_id')->references('id')->on('order_product_status_names');
    });
}

public function up() {
    Schema::create('order_product_status_names', function (Blueprint $table) {
        $table->bigIncrements('id')->unsigned();
        $table->string('name');
        $table->string('code');
        $table->dateTime('created_at')->default(DB::raw('CURRENT_TIMESTAMP'));

        $table->primary('id');
    });
}

HTH你有点。

Laravel关系属于具有复合主键的ToMany

1 个答案: