总计两列作为总数然后减去两个总数

Question

我有这个脚本：

SELECT

  ISNULL([name], 'Total') AS [name]
, [Yesterday]
, [Today]
, [variance]

FROM 
(
  SELECT 
[name],
SUM([yesterday]) AS [yesterday],
SUM([today]) AS [today],
sum(variance) as Variance

  FROM mytable
      GROUP BY [name] WITH ROLLUP
 ) AS DT

返回此表：

name  |yesterday|today|variance
john  | 3       |4    | 0.33
smith | 4       |5    |0.25
daniel| 5       |2    |-0.6
total | 12      |11   |-0.02

其中方差总和实际应为：（11-12）/ 12 = -0.833

如何让我的脚本产生结果而不是总差异列？

预期的数据将是：

name  |yesterday|today|variance
john  | 3       |4    | 0.33
smith | 4       |5    |0.25
daniel| 5       |2    |-0.6
total | 12      |11   |-0.833

Answer 1

你试过这个吗？：

SELECT

  ISNULL([name], 'Total') AS [name]
, [Yesterday]
, [Today]
, [variance]

FROM 
(
  SELECT 
[name],
SUM([yesterday]) AS [yesterday],
SUM([today]) AS [today],
((SUM([today]) -SUM([yesterday]))/SUM([yesterday])) as Variance

  FROM mytable
      GROUP BY [name] WITH ROLLUP
 ) AS DT