邮件发送脚本

时间:2011-01-03 14:06:47

标签: php

///Send mail to members whom subscribed to receive mail

$one = 1;
settype($one, 'integer');

$two = 2;
settype($two, 'integer');

$query_news_mail = "SELECT M.id, M.j_email, M.j_news_alert, M.j_news_catid_notification FROM jt_members M WHERE (M.j_news_alert = $two AND M.j_news_catid_notification = $data[catid]) AND M.j_news_alert = $one;";
$mail_result = mysql_query($query_news_mail) or die(trigger_error(MYSQL_ERROR_MSG,E_USER_ERROR));

while($row_mail = mysql_fetch_assoc($mail_result)) {


//start sending mails here
echo "mail";
}

第二个子句不执行//M.j_news_alert = $ one 任何想法? 感谢

3 个答案:

答案 0 :(得分:1)

也许你的意思

... notice the OR in place of AND ...
(M.j_news_alert = $two AND M.j_news_catid_notification = $data[catid]) OR M.j_news_alert = $one;

否则您无法满足您的WHERE条件:M.j_news_alert = $two AND M.j_news_alert = $one;

答案 1 :(得分:0)

(M.j_news_alert = $two AND M.j_news_catid_notification = $data[catid])
AND M.j_news_alert = $one;

这永远不会是true,所以最终会得到一个空的结果集。

答案 2 :(得分:0)

SELECT M.id,M.j_email,M.j_news_alert,M.j_news_catid_notification 来自jt_members M. WHERE(M.j_news_alert = $ two AND M.j_news_catid_notification = $ data [catid])或M.j_news_alert = $ one;“

是的,我认为你需要并且意味着OR

编辑:看起来有人打败了我。

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