Question

该程序用于在用户输入的指定目录中创建文件。用户还可以指定名称和文件扩展名。将标记对代码的最新更改。我做的最新事情是编写代码，以便程序可以判断用户是否添加了扩展名或扩展名是否有效。

java.lang.ExceptionInInitializerError
Caused by: java.lang.NullPointerException
    at filecreator.coolversion.FileCreatorCoolversion.<clinit>
(FileCreatorCoolversion.java:13)
Exception in thread "main" 
C:\Users\deadm\AppData\Local\NetBeans\Cache\8.2\executor-
snippets\run.xml:53: Java returned: 1

^错误

代码：

package filecreator.coolversion;

import java.io.File;
import java.io.IOException;
import java.util.*;

public class FileCreatorCoolversion {

public static Scanner sc = new Scanner(System.in);
public static boolean success = false;
public static String filename;
public static String filedir;
public static String fileexten = filename.substring(filename.lastIndexOf(".") + 1); //RECENT CHANGE HERE
public static File file;
public static File dir;

public static void main(String[] args) throws IOException {

    System.out.println("********************************");
    System.out.println("* Welcome to File Creator 2.0! *");
    System.out.println("********************************");
    System.out.println(" ");

    while(!success) {

        System.out.println("Would you like to create a file? Y/N?");
        String usrans = sc.nextLine();

        if(usrans.equalsIgnoreCase("y")) {

            System.out.println("Proceeding with file creation...");
            break;

        } else if(usrans.equalsIgnoreCase("n")) {

            System.out.println("Exiting Program...");
            System.exit(0);

        } else if(!usrans.equalsIgnoreCase("y") || !usrans.equalsIgnoreCase("n")) {

            System.out.println("That is not a valid answer! Please try again!");
            System.out.println(" ");
        }
    }

    while(!success) {

        System.out.println(" ");
        System.out.println("Please enter a valid filename:");
        filename = sc.nextLine();

        if(filename.isEmpty()) {

            System.out.println("Please enter a file name!");
            break;

        } else if(filename.contains("/") || filename.contains(":") || 
                  filename.contains("*") || filename.contains("?") ||
                  filename.contains("<") || filename.contains(">") ||
                  filename.contains("|") || filename.contains("\"") ||
                  filename.contains("\\")) {

            System.out.println("Please do not include / \\ : * ? \" < > |");

        } else if(!filename.contains(".")) {

            System.out.println("Please add a apropriate file extensions");

        } else if (!fileexten.isEmpty() || fileexten.contains("[^\\p{IsDigit}\\p{IsAlphabetic}]")) { //RECENT CHANGE HERE

            System.out.println("Please specify a valid file extension!");

        } else {

            System.out.println(" ");
            System.out.println("File name \"" + filename + "\" chosen");
            break;
        }
    }

        System.out.println(" ");
        System.out.println("Where would you like to have your file saved?");
        System.out.println("Please enter a valid directory");

    while(!success) {

        filedir = sc.nextLine();

        if(!filename.contains(":")) {

            System.out.println(" ");
            System.out.println("Please enter a valid directory!");

        } else if(!filename.contains("\\")) {

            System.out.println(" ");
            System.out.println("Please enter a valid directory!");

        } else {

            System.out.println("File directory \"" + filedir + "\" chosen");
            break;
        }
    }

    System.out.println(" ");
    System.out.println("Creating file...");

}

}

我无法分辨出错误的来源请帮助我。我现在对调试程序并不擅长，这是我需要处理的事情之一。请帮帮我。

Answer 1

你不能这样做：

public static String fileexten = filename.substring(filename.lastIndexOf(".") + 1);

您的文件名为null。填充文件名后，在方法内部执行。

Answer 2

filename仍为null。所以先做这个：

public static String fileexten;

然后在给出文件名值后立即初始化：

while(!success) { 
System.out.println(" ");
 System.out.println("Please enter a valid filename:"); 
filename = sc.nextLine();
fileexten = filename.substring(filename.lastIndexOf(".") + 1);

即使没有红线，Java仍然会给我一个错误

2 个答案: