Question

我试图从我有几个表的DataSet生成的XmlSchema对象中提取数据。我下面的示例中的XmlSchema将导出为完整的正确模式，但我不知道如何遍历它。只有一个项目，而元素总是空的。如何访问XmlSchema对象中的表和列元素？

using System;
using System.IO;
using System.Data;
using System.Collections;
using System.Xml.Schema;

public class Program
{
    public static void Main()
    {
        DataTable table1 = new DataTable("patients");
        table1.Columns.Add("name");
        table1.Columns.Add("id", typeof(int));
        table1.Rows.Add("sam", 1);
        table1.Rows.Add("mark", 2);

        DataTable table2 = new DataTable("medications");
        table2.Columns.Add("id", typeof(int));
        table2.Columns.Add("medication");
        table2.Rows.Add(1, "atenolol");
        table2.Rows.Add(2, "amoxicillin");

        DataSet set = new DataSet("office");
        set.Tables.Add(table1);
        set.Tables.Add(table2);

        using (var reader = new StringReader(set.GetXmlSchema()))
        using (var writer = new StringWriter()) 
        {
            var schema = XmlSchema.Read(reader, (sender, args) => { });
            schema.Write(writer);
            writer.Flush();
            Console.WriteLine(schema.Elements.Values.Count);
            Console.WriteLine(writer.ToString());
        }

        //Console.WriteLine(set.GetXmlSchema());
    }
}

Answer 1

我不确定为什么它会以这种方式工作，但这证明您的架构对象已正确填充：

string s = set.GetXmlSchema();
using (TextReader w = new StringReader(s)) {

    XmlSchema x = XmlSchema.Read(w, null);
    XmlSchemaElement e = (XmlSchemaElement)x.Items[0];
    XmlSchemaComplexType t = (XmlSchemaComplexType)e.SchemaType;
    XmlSchemaChoice c = (XmlSchemaChoice)t.Particle;
    XmlSchemaElement e2 = (XmlSchemaElement)c.Items[0];
    Console.WriteLine(e2.Name);
}

正确遍历XmlSchema对象

1 个答案: