Question

我很难找到如何只返回结果集中claimtid的最新迭代。我正在使用此查询：

SELECT
   claimid, paiddate
   CASE
      WHEN actid = '119' THEN 'Channel Exception'
      WHEN actid = '127' THEN 'Rejected'
      WHEN actid = '128' THEN 'Accepted'
      WHEN actid = '130' THEN 'Adjustment Complete'
      WHEN actid = '133' THEN 'Channel Ready'
   END AS [Status]
FROM
    Encounter
WHERE 
    claimtid LIKE '173225AR0%' OR claimtid LIKE '197565GL0%' OR 
    claimtid LIKE '293215QW0%' OR claimtid LIKE
ORDER BY 
    claimtid

此查询返回以下结果：

 |claimtid  |paiddt    |Status             |
-+----------+----------+-------------------+
1|173225AR00|2017-03-01|Adjustment Complete|
2|173225AR01|2017-04-11|Accepted           |
3|197565GL00|2017-03-17|Accepted           |
4|197565GL01|2017-03-19|Adjustment Complete|
5|197565GL02|2017-04-01|Rejected           |
6|293215QW00|2017-04-19|Adjustment Complete|
7|293215QW01|2017-04-23|Accepted           |

我不确定我可以添加到查询中的内容，以便结果只会返回第2行，第5行和第7行。我的实际查询包含会在结果中生成更多行。

这只是一个例子，但对于这种情况是准确的。我需要回退超过3行，但它需要是最新的迭代。

每次额外的迭代都会使claimtid中的最后一个数字增加一个。我不知道每个claimtid有多少次迭代。

Answer 1

试试这个，但我不确定在你的情况下使用字符串for claimtid的性能损失：

SELECT claimid, paiddate
FROM
Encounter
WHERE claimtid IN (
    SELECT MAX(paiddt), claimtid  
    FROM Encounter
    GROUP BY SUBSTRING (claimtid, 6, 8)
) t

假设您可以依靠paydate字段来了解最新记录。

Answer 2

如果您无法将声明ID的两个字段分隔为数据表本身的单独列，则可以在查询中将它们分开，以允许您使用max()聚合查找第二个字段的最大值。

select
    claim,
    paiddate,
    CASE
        WHEN actid = '119' THEN 'Channel Exception'
        WHEN actid = '127' THEN 'Rejected'
        WHEN actid = '128' THEN 'Accepted'
        WHEN actid = '130' THEN 'Adjustment Complete'
        WHEN actid = '133' THEN 'Channel Ready'
        END AS [Status]
from
    (
        select
            left(claimid, 6) as claim,
            max(right(claimid,4)) as seq,
        from
            Encounter
        group by
            left(claimid, 6)
    ) as ms
    inner join Encounter as e
        on e.claimid = ms.claim + ms.seq;

Answer 3

这应该可以解决问题......

IF OBJECT_ID('tempdb..#ClaimData', 'U') IS NOT NULL 
DROP TABLE #ClaimData;

CREATE TABLE #ClaimData (
    RN INT NOT NULL IDENTITY(1,1),
    claimtid CHAR(10) NOT NULL,
    paiddt DATE NOT NULL,
    [Status] VARCHAR(20) NOT NULL 
    );
INSERT #ClaimData (claimtid, paiddt, Status) VALUES

    ('173225AR00', '2017-03-01', 'Adjustment Complete'),
    ('173225AR01', '2017-04-11', 'Accepted'),
    ('197565GL00', '2017-03-17', 'Accepted'),
    ('197565GL01', '2017-03-19', 'Adjustment Complete'),
    ('197565GL02', '2017-04-01', 'Rejected'),
    ('293215QW00', '2017-04-19', 'Adjustment Complete'),
    ('293215QW01', '2017-04-23', 'Accepted');

--SELECT * FROM #ClaimData cd;

--=========================================================

SELECT TOP 1 WITH TIES 
    cd.RN, cd.claimtid, cd.paiddt, cd.Status
FROM
    #ClaimData cd
    CROSS APPLY ( VALUES (SUBSTRING(cd.claimtid, 1, 6), SUBSTRING(cd.claimtid, 7, 4)) ) sc (Claim_1, Claim_2)
ORDER BY 
    ROW_NUMBER() OVER (PARTITION BY sc.Claim_1 ORDER BY sc.Claim_2 DESC);

结果...

RN          claimtid   paiddt     Status
----------- ---------- ---------- --------------------
2           173225AR01 2017-04-11 Accepted
5           197565GL02 2017-04-01 Rejected
7           293215QW01 2017-04-23 Accepted

编辑... 性能稍好的解决方案可以产生相同的结果...

SELECT 
    RN = CAST(SUBSTRING(MAX(bv.BinaryValue), 39, 4) AS INT),
    claimtid = CAST(SUBSTRING(MAX(bv.BinaryValue), 1, 10) AS CHAR(10)),
    paiddt = CAST(SUBSTRING(MAX(bv.BinaryValue), 11, 8) AS DATE),
    Status = CAST(SUBSTRING(MAX(bv.BinaryValue), 19, 20) AS VARCHAR(20))
FROM
    #ClaimData cd
    CROSS APPLY ( VALUES (CAST(cd.claimtid AS BINARY(10)) + CAST(cd.paiddt AS BINARY(8)) + CAST(cd.Status AS BINARY(20)) + CAST(cd.RN AS BINARY(4))) ) bv (BinaryValue)
GROUP BY 
    SUBSTRING(cd.claimtid, 1, 6);

Answer 4

尝试这一点，假设你不能及早获得以后付款的声明：

IF OBJECT_ID('tempdb..#ClaimData') IS NOT NULL 
DROP TABLE #ClaimData

CREATE TABLE #ClaimData (
    ID INT NOT NULL IDENTITY(1,1)
    , claimtid CHAR(10) NOT NULL
    , paiddt DATE NOT NULL
    , [Status] VARCHAR(20) NOT NULL 
)
INSERT #ClaimData (claimtid, paiddt, Status) VALUES

    ('173225AR00', '2017-03-01', 'Adjustment Complete')
    ,('173225AR01', '2017-04-11', 'Accepted')
    ,('197565GL00', '2017-03-17', 'Accepted')
    ,('197565GL01', '2017-03-19', 'Adjustment Complete')
    ,('197565GL02', '2017-04-01', 'Rejected')
    ,('293215QW00', '2017-04-19', 'Adjustment Complete')
    ,('293215QW01', '2017-04-23', 'Accepted')

SELECT
    ID
    , x.claimtid
    , x.paiddt
    , x.Status
FROM (
    SELECT
        ROW_NUMBER() OVER (PARTITION BY LEFT(Claimtid, LEN(Claimtid) - 2) ORDER BY paiddt DESC) RN
        , *
    FROM #ClaimData
) x
WHERE x.RN = 1

否则将RN更改为ROW_NUMBER() OVER (PARTITION BY LEFT(Claimtid, LEN(Claimtid) - 2) ORDER BY RIGHT(Claimtid, 2) DESC) RN

我怎样才能只撤回SQL中的最新结果？

4 个答案: