Question

我在一个非常简单的表单验证脚本中遇到了一个奇怪的问题。使用Chrome和Firefox没有任何问题，但使用safari我的<p>的innerHTML无法正确更改。第二个问题是我无法在代码段中显示它，因为代码片段太小。如果用户首先键入@然后输入一个数字并再次删除该数字，则会收到混合错误消息。（错误消息3和消息6的第二行）。如果我只是手动重新缩放safari窗口，第二行就会消失。使用/和数字或a的组合也会发生同样的情况。和一个数字。就像你在代码中看到的一样。

网站预览：Preview

为了产生错误/错误，我在绿色框中的第三个img中解决了这个问题：填写@ 添加一个号码删除号码

这是我的HTML：

<h3 id="forms">Forms</h3>
<div class="forms">
    <form>
        <div class="input"><input placeholder="name" name="name" type="text" oninput="checkname(this.id)" id="name"><div><p id="namereaction" class="reaction"></p></div></div>
        <div class="input"><input placeholder="firstname" name="name" type="text" oninput="checkname(this.id)" id="firstname"><div><p id="firstnamereaction" class="reaction"></p></div></div>
        <div class="input"><input placeholder="mail" name="mail" type="email" oninput="checkmail()" id="mail"><div><p id="mailreaction" class="reaction"></p></div></div>
        <div class="input"><textarea name="text" id="textarea"></textarea><div id="textreactionbox"><p id="textareareaction" class="reaction"></p></div></div>
        <div class="input"><input type="submit" name="submit" value="submit"></div>
    </form>
</div>

我的JS：

function checkname(id){
    var error="";
    var value = document.getElementById(id).value;
    if(value.length<1){
        error = "Please fill in your (first)name.";
    }
    if(value.length>50){
        error = "Please fill in your (first)name. Your name is to long.";
    }
    if (value.indexOf("@") > -1 ) {
        error = "I think you are filling in your emailadress";
    }
    if (value.indexOf(".") > -1 ) {
        error = "Please check your (first)name, most names don't have a '.'.";
    }
    if (value.indexOf("/") > -1 ) {
        error = "Please check your (first)name, most names don't have a '/'.";
    }
    var matches = value.match(/\d+/g);
    if (matches != null) {
        error = "Please check your (first)name, we are all people, our (first)name doesn't contain a number.";
    }
    if(error.length>1){
        document.getElementById(id+"reaction").innerHTML=error;
    }else{
        document.getElementById(id+"reaction").innerHTML="";
    }
}

Answer 1

这似乎是Safari的渲染错误，因为我只能在Safari中重现它：

特定的自定义字体（Aqua，在其他自定义字体上，它不可重现）;
特定的块大小（当有2行文本时）。

由于CORS问题，Chrome和Firefox并未真正加载字体：

但Safari可以，您可以在this JSFiddle上查看。

此片段仅针对历史记录，因为您网站上的特定字体仅可通过HTTP使用（但SO片段需要HTTPS）：

＆＃13;

function checkname(id) {
  var error = "";
  var value = document.getElementById(id).value;
  if (value.length < 1) {
    error = "Please fill in your (first)name.";
  }
  if (value.length > 50) {
    error = "Please fill in your (first)name. Your name is to long.";
  }
  if (value.indexOf("@") > -1) {
    error = "I think you are filling in your emailadress";
  }
  if (value.indexOf(".") > -1) {
    error = "Please check your (first)name, most names don't have a '.'.";
  }
  if (value.indexOf("/") > -1) {
    error = "Please check your (first)name, most names don't have a '/'.";
  }
  var matches = value.match(/\d+/g);
  if (matches != null) {
    error = "Please check your (first)name, we are all people, our (first)name doesn't contain a number.";
  }
  if (error.length > 1) {
    document.getElementById(id + "reaction").innerHTML = error;
  } else {
    document.getElementById(id + "reaction").innerHTML = "";
  }
}

＆＃13;

@font-face {
  font-family: "Aqua";
  src: url(http://north-wind.be/css/aqua.ttf) format("truetype");
}

.input {
  width: 100%;
  overflow: auto;
  margin: 24px auto;
  font-family: Aqua, Arial;
}

.input input[type=text],
.input input[type=email] {
  border: 1pt solid limegreen;
  width: 150px;
  border-radius: 8px 0px 0px 8px;
  height: 40px;
  margin: 0;
  float: left;
  font-size: 20px;
}

.input div {
  border-radius: 0px 8px 8px 0px;
  width: 350px;
  background: limegreen;
  color: white;
  height: 36px;
  float: left;
  padding: 4px 0;
  margin: 0;
  vertical-align: middle;
}

.input div p {
  vertical-align: middle;
  text-align: center;
  margin: 0 auto;
  border: none;
  padding: 0;
  width: 100%;
  height: 100%;
  font-size: 12px;
  color: white;
}

＆＃13;

<h3 id="forms">Forms</h3>
<div class="forms">
  <form>
    <div class="input">
      <input placeholder="name" name="name" type="text" oninput="checkname(this.id)" id="name">
      <div>
        <p id="namereaction" class="reaction"></p>
      </div>
    </div>
    <div class="input">
      <input type="submit" name="submit" value="submit">
    </div>
  </form>
</div>

＆＃13;

所以，我只建议您使用one of force redraw/repaint hacks，例如：

var element = document.getElementById(id + 'reaction');
if (error.length > 1) {
  element.innerHTML = error;
} else {
  element.innerHTML = '';
}
element.style.display = 'none';
element.offsetHeight;
element.style.display = '';

The fixed JSFiddle

Safari JS innerHTML错误/错误

1 个答案: