Question

我是Linux上的C ++编程新手。我尝试使用旋转编码器来控制液晶显示屏上的值。根据我使用的wirePi设置例程，只有中断或lcd工作，但不能同时进行。我导出了所有nessersary GPIO，因此不需要sudo。

#Interrupt Pins Encoder
gpio edge 23 both
gpio edge 24 both
gpio mode 4 up
gpio mode 5 up

#Pins LCD
gpio export 17 out
gpio export 18 out
gpio export 27 out
gpio export 22 out
gpio export 8 out
gpio export 7 out

这里是C ++代码：

#include <wiringPi.h>
#include <lcd.h>
#include <stdio.h>

#define A   23
#define B   24

char a = 0;
char b = 0;
const char a1 = 1, a2 = 2, a3 = 3, b1 = 4, b2 = 5, b3 = 6;
char state = 0;

volatile int counter = 0;
volatile int counter_l = 0;
void interrupt();

int main(void)
{
    printf("wiringPiSetup\n");
    //wiringPiSetupSys();  //Interrupts working
    wiringPiSetup();  //LCD working

    pinMode(17, OUTPUT);
    pinMode(18, OUTPUT);
    pinMode(27, OUTPUT);
    pinMode(22, OUTPUT);
    pinMode(8, OUTPUT);
    pinMode(7, OUTPUT);

    int fd = lcdInit(2, 16, 4, 11, 10, 0, 1, 2, 3, 0, 0, 0, 0);
    lcdClear(fd);
    lcdPosition(fd, 0, 0);
    lcdPrintf(fd,"Test");

    wiringPiISR(A, INT_EDGE_BOTH, &interrupt);
    wiringPiISR(B, INT_EDGE_BOTH, &interrupt);

    pinMode(A, INPUT);
    pinMode(B, INPUT);

    while (true)
    {
        if (counter != counter_l)
        {
            counter_l = counter;
            printf("%i\n", counter);
            lcdPosition(fd, 0, 0);
            lcdPrintf(fd, "%i   ", counter);
        }
    }
    return 0;
}

void interrupt(){
    a = !digitalRead(A);
    b = !digitalRead(B);
    switch (state)
    {
    case a1:
        if (!a) 
            state = 0;
        else if (b) 
            state = a2;
        break;
    case a2:
        if (!a&&b)
            state = a3;
        else if (a&&!b)
            state = a1;
        break;
    case a3:
        if (a&&b)
            state = a2;
        else if (!a&&!b) {
            state = 0;
            counter++;
        }
        break;
    case b1:
        if (!b)
            state = 0;
        else if (a)
            state = b2;
        break;
    case b2:
        if (!b&&a)
            state = b3;
        else if (b&&!a)
            state = b1;
        break;
    case b3:
        if (b&&a)
            state = b2;
        else if (!b&&!a) {
            state = 0;
            counter--;
        }
        break;
    default:
        if (a&&b) 
            state = 0;
        else if (a)
            state = a1;
        else if (b)
            state = b1;
        break;
    }   
}

现在问题是为什么它表现得像那样，我能做什么/应该做什么。

Answer 1

我找到了与设置功能一起使用的不同编号的解决方案。 WirinpPi有自己的Pin编号，还有原生的BCM编号。解决方案是将lcdInit函数中的编号更改为BCM编号。

                        //wiringPi Nr.
pinMode(17, OUTPUT);    //0
pinMode(18, OUTPUT);    //1
pinMode(27, OUTPUT);    //2
pinMode(22, OUTPUT);    //3
pinMode(8, OUTPUT);     //10
pinMode(7, OUTPUT);     //11

//int fd = lcdInit(2, 16, 4, 11, 10, 0, 1, 2, 3, 0, 0, 0, 0);   //wiringPi Nr.
int fd = lcdInit(2, 16, 4, 7, 8, 17, 18, 27, 22, 0, 0, 0, 0);   //BCM Nr.

同时使用带有中断和lcd的wiringPi

1 个答案: