Question

我有下表Employee：

+----+--------+
| Id | Salary |
+----+--------+
| 1  | 150    |
| 2  | 290    |
| 3  | 302    |
+----+--------+

我使用以下代码找到第二高薪：

with t as 
(
    select 
        Salary, 
        row_number() over (order by Salary desc) as salary_ord 
    from 
        Employee
)
select Salary 
from t 
where salary_ord == 2

然而，我收到错误：

SyntaxError：near＆＃t; t as（
选择Salary，row_number（）over（Salary desc的顺序）作为salary_ord＆＃39;

我在这里做错了什么？谢谢！

Answer 1

在SQL中，正确的比较运算符为=，而不是==。因此，这是查询的ANSI SQL版本：

with t as (
      select Salary, row_number() over (order by Salary desc) as salary_ord 
      from Employee
     )
select Salary
from t
where salary_ord = 2;

但是，您的错误表明您的数据库不支持with或窗口函数。

Answer 2

在SQL Server中，

你可以这样做：

select top 1 Salary 
from Employee 
order by Salary desc
offset 1 row fetch next 1 row only

SQL：SyntaxError：order by row_number（）函数

2 个答案: