Question

代码会一直打开login.php，其中包含错误和正确的登录详细信息。我打算每次有人尝试登录时启动一个会话，但只允许经过身份验证的尝试

<?php    
function login() {
     global $con;
     if (isset($_POST['submit'])){
       // $member_id = $_POST['member_id'];
       // $memberpass = $_POST['memberpass'];



    if( isset($_POST['member_id']) && isset($_POST['memberpass'])){

        $sql= "SELECT * from login ";
        $query=query($sql);


    if(isset($_SESSION["user"]))
        {
            if ($_SESSION['member_id'] = $_POST['member_id'] && $_SESSION['memberpass'] = $_POST['memberpass']);
            session_start();


            header('Location: index1.php');
        }
        else {
            header('Location: login.php');
        }
?>

Answer 1

修复PHP会话问题

<?php    
session_start();

//For debuging purpose
error_reporting(E_ALL); 
ini_set('display_errors', true);

print_r( $_SESSION );

function login() {
     global $con;
     if (isset($_POST['submit'])){
       // $member_id = $_POST['member_id'];
       // $memberpass = $_POST['memberpass'];



    if( isset($_POST['member_id']) && isset($_POST['memberpass'])){

        $sql= "SELECT * from login ";
        $query=query($sql);


    if(isset($_SESSION["user"]))
        {
            // remove semi colon at the end ;if ($_SESSION['member_id'] = $_POST['member_id'] && $_SESSION['memberpass'] = $_POST['memberpass']);
            if ($_SESSION['member_id'] == $_POST['member_id'] && $_SESSION['memberpass'] == $_POST['memberpass'])
            {
                header('Location: index1.php');
            }
            else {
               echo "Invalid User";
               //header('Location: login.php');
            }
        }
        else {
            header('Location: login.php');
        }
?>

第24行通过删除末尾的半冒号并为逻辑
添加了error_reporting以让您看到任何错误。

希望这有帮助。

php会话保持重定向到一个页面

1 个答案:

修复PHP会话问题