Question

createUser方法有效，但loginUser方法不断返回true无效的登录参数。它将用户注册到数据库中，但无法将其登录：

{"error":true,"message":"Invalid login parameters!"}

我正在使用Postman

测试我的代码

这些是方法：

public function createUser($username,$pass,$email){
    if($this->isUserExist($username,$email)){
        return 0;
    }else{
        $password = md5($pass);
        $stmt = $this->con->prepare("INSERT INTO `users`(`id`,`username`, `password`, `email`) VALUES (null, ?, ?, ?);");
                                    $stmt->bind_param("sss",$username,$password,$email);

        if($stmt->execute()){
            return 1;
        }else{
            return 2;
        }
    }
}

public function userLogin($username, $pass){
    $password = md5($pass);
    $stmt = $this->con->prepare("SELECT `id` FROM `users` WHERE `username` = ? AND `password` = ?");
    $stmt->bind_param("ss", $username,$password);
    $stmt->execute();
    //$stmt->store_result();
    return $stmt->num_rows > 0;
}

public function getUserByUsername($username){
    $stmt = $this->con->prepare("SELECT * FROM `users` WHERE `username` = ?");
    $stmt->bind_param("s",$username);
    $stmt->execute();
    return $stmt->get_result()->mysqli_fetch_assoc();
}

private function isUserExist($username, $email){
   $stmt = $this->con->prepare("SELECT `id` FROM `users` WHERE `username` = ? OR `email` = ?");
   $stmt->bind_param("ss", $username,$email);
   $stmt->execute();
   $stmt->store_result();
   return $stmt->num_rows > 0;
}

这是我调用方法的地方：

require_once '../includes/DbOperations.php';
$response = array();

if($_SERVER['REQUEST_METHOD']=='POST'){
    if(isset($_POST['username']) and isset($_POST['password'])){
        $db = new DbOperations();
        if($db->userLogin($_POST['username'],$_POST['password'])){
        $user = $db->getUserByUsername($_POST['username']);
        $response['error'] = false;
        $response['id'] = $user['id'];
        $response['email'] = $user['email'];
        $response['username'] = $user['username'];

    }else{
        $response['error'] = true;
        $response['message'] = "Invalid login parameters!";
    }

    }else{
        $response['error'] = true;
        $response['message'] = "Required fields are missing!";
    }
}

echo json_encode($response);

为什么我的登录方法失败？

0 个答案: