Question

我试图在beetwen我的php中添加一个空格，我需要在输出后添加一个空格并删除最后一个输出的逗号。这是我的代码

<div id="demo-1" data-zs-src='[
    <?php
    $sql = "SELECT * FROM slider ORDER BY no_urut ASC";
    $result = mysqli_query($conn, $sql);
    if (mysqli_num_rows($result) > 0) {
        while ($data = mysqli_fetch_assoc($result)) {
            echo "\"images/slideshow/".$data['img']."\",";
        }
    }
    ?>
]' data-zs-overlay="dots"></div>

当我运行该代码时，就像这样

data-zs-src="["images/slideshow/img1.jpg","images/slideshow/img2.jpg","images/slideshow/img3.jpg",]"

但我希望代码像这样

data-zs-src="["images/slideshow/img1.jpg", "images/slideshow/img2.jpg", "images/slideshow/img3.jpg"]"

Answer 1

您可以进行分配并检入单个if语句，使用结果形成数组，然后使用,（逗号空格）内爆。

<div id="demo-1" data-zs-src="[
    <?php
    if($result=mysqli_query($conn,'SELECT `img` FROM `slider` ORDER BY `no_urut` ASC;') && mysqli_num_rows($result)){
        while($data=mysqli_fetch_assoc($result)){
            $imgs[]="\"images/slideshow/{$data['img']}\"";
        }
        echo implode(', ',$imgs);
    }
    ?>
]" data-zs-overlay="dots"></div>

或者使用原始的单行风格：

<div id="demo-1" data-zs-src="[<?php if($result=mysqli_query($conn,'SELECT `img` FROM `slider` ORDER BY `no_urut` ASC;') && mysqli_num_rows($result)){while($data=mysqli_fetch_assoc($result)){$imgs[]="\"images/slideshow/{$data['img']}\"";}; echo implode(', ',$imgs);}?>]" data-zs-overlay="dots"></div>

在php中输出之间添加空格

1 个答案: