Question

在我上传.php并在本地使用它之前，这是我的代码。

        public function getUserByCardNo($cardno){
        $stmt = $this->con->prepare("SELECT * FROM accounts WHERE cardno = ?");
        $stmt->bind_param("s",$cardno);
        $stmt->execute();
        return $stmt->get_result()->fetch_assoc(); 
    }

我将.php上传到免费托管网站。运行后，我收到错误：调用未定义的方法mysqli_stmt :: get_result（）

经过一番挖掘后，我找到了这个答案：stackoverflow.com

他们说我需要使用BIND_RESULT＆amp;取。但是我不知道在 while（$ stmt-＆gt; fetch（））块中写什么

所以，我一直在挖掘并找到了这个：stackoverflow.com

现在是我的代码：

        public function getUserByCardNo($cardno){
        $stmt = $this->con->prepare("SELECT id, name, cardno, pin, balance, status FROM accounts WHERE cardno = ?");
        $stmt->bind_param("s",$cardno);
        $stmt->execute();
        $stmt->bind_result($id, $name, $cardno, $pin, $balance, $status);
        $info = array();
        while ($stmt->fetch()){
            $tmp = array();
            $tmp["id"] = $id;
            $tmp["name"] = $name;
            $tmp["cardno"] = $cardno;
            $tmp["pin"] = $pin;
            $tmp["balance"] = $balance;
            $tmp["status"] = $status;
            array_push($info, $tmp);
        }
        $stmt->close();
        return $info;
    }

该函数由我的userLogin.php调用

if($_SERVER['REQUEST_METHOD']=='POST'){
if(isset($_POST['cardno']) and isset($_POST['pin'])){
    $db = new DbOperations();
    if($db->userLogin($_POST['cardno'], $_POST['pin'])){
        $user = $db->getUserByCardNo($_POST['cardno']);
        $response['error'] = false;
        $response['id'] = $user['id'];
        $response['pin'] = $user['pin'];
        $response['cardno'] = $user['cardno'];
        $response['name'] = $user['name'];
        $response['balance'] = $user['balance'];
        $response['status'] = $user['status'];

    }
    else{
        $response['error'] = true;
        $response['message'] = "Invalid Card Number or Pin";
    }
}
else{
    $response['error'] = true;
    $response['message'] = "Required fields are missing";
}

}

因为我需要存储所有用户的信息。

但是在使用Postman后，我得到了这个结果。

{ “错误”：假， “ID”：NULL， “针”：NULL， “cardno”：空， “姓名”：空， “平衡”：NULL， “状态”：空} < /强>

它返回的所有内容都为空。

Answer 1

n将位于数字索引数组中。因此，您需要使用$user代替$user[0]['id']。

如果单个$user['id']可以有多个记录，则还需要遍历cardno数组（如果需要，也就是这样）。

Answer 2

像这样改变上面的代码

if($_SERVER['REQUEST_METHOD']=='POST'){
        if(isset($_POST['cardno']) and isset($_POST['pin'])){
            $db = new DbOperations();
            if($db->userLogin($_POST['cardno'], $_POST['pin'])){
                $user = $db->getUserByCardNo($_POST['cardno']);
                $response['error'] = false;
                $response['id'] = $user[0]['id'];
                $response['pin'] = $user[0]['pin'];
                $response['cardno'] = $user[0]['cardno'];
                $response['name'] = $user[0]['name'];
                $response['balance'] = $user[0]['balance'];
                $response['status'] = $user[0]['status'];

            }
            else{
                $response['error'] = true;
                $response['message'] = "Invalid Card Number or Pin";
            }
        }
        else{
            $response['error'] = true;
            $response['message'] = "Required fields are missing";
        }

bind_result和fetch返回null

2 个答案: