从2d数组中删除重复项

时间:2017-09-11 14:22:39

标签: javascript arrays

var result = [
  [0, 0, 0, -2],
  [0, 0, -2, 0],
  [0, 0, 0, -2],
  [0, 0, -2, 0],
  [0, -2, 0, 0],
  [0, -2, 0, 0],
  [0, 0, 0, -2],
  [0, 0, -2, 0],
  [0, 0, 0, -2],
  [0, 0, -2, 0],
  [0, -2, 0, 0],
  [0, -2, 0, 0],
  [0, 0, 0, -2],
  [0, 0, -2, 0],
  [0, 0, 0, -2],
  [0, 0, -2, 0],
  [0, -2, 0, 0],
  [0, -2, 0, 0],
  [-2, 0, 0, 0],
  [-2, 0, 0, 0],
  [-2, 0, 0, 0],
  [-2, 0, 0, 0],
  [-2, 0, 0, 0],
  [-2, 0, 0, 0]
];
for (var i = 0; i < result.length; i++) { //remove duplicates
  var listI = result[i];
  loopJ: for (var j = 0; j < result.length; j++) {
    var listJ = result[j]; //listJ and listI point at different arrays within the result array
    if (listI === listJ) continue; //Ignore itself
    for (var k = listJ.length; k >= 0; k--) { //checks whether the values are different, if they are continue with the loop
      if (listJ[k] !== listI[k]) continue loopJ;
    }
    // At this point, their values are equal so we remove from the result array
    result.splice(j, 1);
  }
}
document.getElementById("result").innerHTML = JSON.stringify(result);
<div id="result">

</div>

我正在尝试从我的程序在置换2d数组时创建的某些数据中删除重复项,但在某些情况下,它无法删除所有重复项。我有点迷失为什么,代码很短并且注释了,我在结果变量下的输入2d数组中进行了硬编码。

3 个答案:

答案 0 :(得分:3)

https://jsfiddle.net/h26ro89p/2/

执行拼接时忘了回溯一个索引:

    result.splice(j, 1);
    j--;

为了防止将来出现这种情况,您可以反转循环甚至使用while循环。通过一些古老的英雄谷歌搜索,你可以在这里找到解决方案:

Remove items from array with splice in for loop

答案 1 :(得分:0)

我将使用lodash

添加更短的内容

https://jsfiddle.net/h26ro89p/3/

        var result = [[0,0,0,-2],[0,0,-2,0],[0,0,0,-2],[0,0,-2,0],[0,-2,0,0],[0,-2,0,0],[0,0,0,-2],[0,0,-2,0],[0,0,0,-2],[0,0,-2,0],[0,-2,0,0],[0,-2,0,0],[0,0,0,-2],[0,0,-2,0],[0,0,0,-2],[0,0,-2,0],[0,-2,0,0],[0,-2,0,0],[-2,0,0,0],[-2,0,0,0],[-2,0,0,0],[-2,0,0,0],[-2,0,0,0],[-2,0,0,0]];


document.getElementById("result").innerHTML = JSON.stringify(_.uniqWith(result, _.isEqual));

答案 2 :(得分:0)

检查这个小提琴https://jsfiddle.net/c2uk0xow/3/,你需要JQuery来使用$ .each函数。

var arr = [
      [0, 0, 0, -2],
      [0, 0, -2, 0],
      [0, 0, 0, -2],
      [0, 0, -2, 0],
      [0, -2, 0, 0],
      [0, -2, 0, 0],
      [0, 0, 0, -2],
      [0, 0, -2, 0],
      [0, 0, 0, -2],
      [0, 0, -2, 0],
      [0, -2, 0, 0],
      [0, -2, 0, 0],
      [0, 0, 0, -2],
      [0, 0, -2, 0],
      [0, 0, 0, -2],
      [0, 0, -2, 0],
      [0, -2, 0, 0],
      [0, -2, 0, 0],
      [-2, 0, 0, 0],
      [-2, 0, 0, 0],
      [-2, 0, 0, 0],
      [-2, 0, 0, 0],
      [-2, 0, 0, 0],
      [-2, 0, 0, 0]
    ];
    var _tmp_arr = [];
    var result = [];
    $.each(arr, function(i,v)
    {
        if(!_tmp_arr.includes(JSON.stringify(v)))
        {
            _tmp_arr.push(JSON.stringify(v));
        }
    });

    $.each(_tmp_arr, function(i,v)
    {
        result.push(JSON.parse(v));
    });
  

注意:我必须转换为字符串,然后再次解析,以便比较两个结果。 [-2,0,0,0] === [-2,0,0,0]返回false,但在我对其进行字符串化后,它为true,"[-2,0,0,0]" === "[-2,0,0,0]"